package main import ( "bufio" "fmt" "os" "sort" "strconv" "strings" ) var sc = bufio.NewScanner(os.Stdin) var wr = bufio.NewWriter(os.Stdout) func out(x ...interface{}) { fmt.Fprintln(wr, x...) } func getI() int { sc.Scan() i, e := strconv.Atoi(sc.Text()) if e != nil { panic(e) } return i } func getF() float64 { sc.Scan() i, e := strconv.ParseFloat(sc.Text(), 64) if e != nil { panic(e) } return i } func getInts(N int) []int { ret := make([]int, N) for i := 0; i < N; i++ { ret[i] = getI() } return ret } func getS() string { sc.Scan() return sc.Text() } // min, max, asub, absなど基本関数 func max(a, b int) int { if a > b { return a } return b } func min(a, b int) int { if a < b { return a } return b } func asub(a, b int) int { if a > b { return a - b } return b - a } func abs(a int) int { if a >= 0 { return a } return -a } func lowerBound(a []int, x int) int { idx := sort.Search(len(a), func(i int) bool { return a[i] >= x }) return idx } func upperBound(a []int, x int) int { idx := sort.Search(len(a), func(i int) bool { return a[i] > x }) return idx } const inf = int(1e18) func main() { defer wr.Flush() sc.Split(bufio.ScanWords) sc.Buffer([]byte{}, 1000000) // this template is new version. // use getI(), getS(), getInts(), getF() N, K := getI(), getI() s := make([]string, N) c := make([]int, N) for i := 0; i < N; i++ { s[i] = getS() c[i] = getI() } cntj := make([]int, N) cnto := make([]int, N) cnti := make([]int, N) for i := 0; i < N; i++ { cntj[i] = strings.Count(s[i], "J") cnto[i] = strings.Count(s[i], "O") cnti[i] = strings.Count(s[i], "I") } cost := make([]int, K*3+1) for i := 0; i < len(cost); i++ { cost[i] += inf } cost[0] = 0 for i := 0; i < K*3; i++ { { if cost[i] < cost[i+1] { for j := 0; j < N; j++ { if i+100 < K { cost[i+cntj[j]] = min(cost[i+cntj[j]], cost[i]+c[j]) } else if i >= K && i+100 < K*2 { cost[i+cnto[j]] = min(cost[i+cnto[j]], cost[i]+c[j]) } else if i >= K*2 && i+100 < K*3 { cost[i+cnti[j]] = min(cost[i+cnti[j]], cost[i]+c[j]) } else { now := i for _, c := range s[j] { if now < K && c == 'J' { now++ } if now >= K && now < K*2 && c == 'O' { now++ } if now >= K*2 && now < K*3 && c == 'I' { now++ } } cost[now] = min(cost[now], cost[i]+c[j]) } } } } } if cost[len(cost)-1] == inf { out(-1) return } out(cost[len(cost)-1]) }