/** * @FileName a.cpp * @Author kanpurin * @Created 2020.11.03 19:24:46 **/ #include "bits/stdc++.h" using namespace std; typedef long long ll; template < int MOD > struct mint { public: long long x; mint(long long x = 0) : x((x % MOD + MOD) % MOD) {} mint(std::string& s) { long long z = 0; for (int i = 0; i < s.size(); i++) { z *= 10; z += s[i] - '0'; z %= MOD; } this->x = z; } mint& operator+=(const mint& a) { if ((x += a.x) >= MOD) x -= MOD; return *this; } mint& operator-=(const mint& a) { if ((x += MOD - a.x) >= MOD) x -= MOD; return *this; } mint& operator*=(const mint& a) { (x *= a.x) %= MOD; return *this; } mint& operator/=(const mint& a) { long long n = MOD - 2; mint u = 1, b = a; while (n > 0) { if (n & 1) { u *= b; } b *= b; n >>= 1; } return *this *= u; } mint operator+(const mint& a) const { mint res(*this); return res += a; } mint operator-() const { return mint() -= *this; } mint operator-(const mint& a) const { mint res(*this); return res -= a; } mint operator*(const mint& a) const { mint res(*this); return res *= a; } mint operator/(const mint& a) const { mint res(*this); return res /= a; } friend std::ostream& operator<<(std::ostream& os, const mint& n) { return os << n.x; } friend std::istream& operator>>(std::istream& is, mint& n) { long long x; is >> x; n = mint(x); return is; } bool operator==(const mint& a) const { return this->x == a.x; } bool operator!=(const mint& a) const { return this->x != a.x; } mint pow(long long k) const { mint ret = 1; mint p = this->x; while (k > 0) { if (k & 1) { ret *= p; } p *= p; k >>= 1; } return ret; } }; constexpr int MOD = 1e9 + 7; // Σ[i=1→N]f(N/i) mint floor_sum(ll N, function(ll)> f) { mint ans = 0;ll i = 1; for (; i * i <= N; i++) ans += f(N/i); for (ll k = 1; k < N/(i-1); k++) ans += f(k) * (N/k - N/(k+1)); return ans; } int main() { int n; cin >> n; mint< MOD > ans = 0; // B|C かつ A,B,Cは異なる ans += floor_sum(n,[](ll a) {return mint(a) - 1;}); ans *= n - 2; // B|A かつ B|C かつ A,B,Cは異なる ans -= floor_sum(n,[](ll a){return mint(a - 1) * (a - 2);}); // A|B かつ B|C かつ A,B,Cは異なる ans -= floor_sum(n,[](ll a){return floor_sum(a,[](ll b){return mint(b)-1;})-a+1;}); cout << ans << endl; return 0; }