#include using namespace std; using lint = long long int; using P = pair; using PL = pair; #define FOR(i, begin, end) for(int i=(begin),i##_end_=(end);i=i##_begin_;i--) #define REP(i, n) FOR(i,0,n) #define IREP(i, n) IFOR(i,0,n) #define ALL(a) (a).begin(),(a).end() constexpr int MOD = 1000000007; constexpr lint B1 = 1532834020; constexpr lint M1 = 2147482409; constexpr lint B2 = 1388622299; constexpr lint M2 = 2147478017; constexpr int INF = 2147483647; void yes(bool expr) {cout << (expr ? "Yes" : "No") << "\n";} templatevoid chmax(T &a, const T &b) { if (avoid chmin(T &a, const T &b) { if (b> N >> M; vector c(2*N*N, 1); vector d(2*N*N, 1e18); d[0] = 0; REP(i, M) { int h, w, cc; cin >> h >> w >> cc; h--; w--; c[h*N+w] += cc; c[h*N+w+N*N] += cc; } set st; st.insert(PL(0, 0)); while(!st.empty()) { PL pl = *st.begin(); st.erase(pl); lint dnow = pl.first; lint h = (pl.second % (N*N)) / N; lint w = pl.second % N; //cout << pl.second << " " << h << " " << w << endl; if(h != 0) { if(dnow + c[pl.second-N] < d[pl.second-N]) { d[pl.second-N] = dnow + c[pl.second-N]; st.insert(PL(d[pl.second-N], pl.second-N)); } if(pl.second < N*N && dnow + 1 < d[pl.second-N+N*N]) { d[pl.second-N+N*N] = dnow + 1; st.insert(PL(d[pl.second-N+N*N], pl.second-N+N*N)); } } if(h != N-1) { if(dnow + c[pl.second+N] < d[pl.second+N]) { d[pl.second+N] = dnow + c[pl.second+N]; st.insert(PL(d[pl.second+N], pl.second+N)); } if(pl.second < N*N && dnow + 1 < d[pl.second+N+N*N]) { d[pl.second+N+N*N] = dnow + 1; st.insert(PL(d[pl.second+N+N*N], pl.second+N+N*N)); } } if(w != 0) { if(dnow + c[pl.second-1] < d[pl.second-1]) { d[pl.second-1] = dnow + c[pl.second-1]; st.insert(PL(d[pl.second-1], pl.second-1)); } if(pl.second < N*N && dnow + 1 < d[pl.second-1+N*N]) { d[pl.second-1+N*N] = dnow + 1; st.insert(PL(d[pl.second-1+N*N], pl.second-1+N*N)); } } if(w != N-1) { if(dnow + c[pl.second+1] < d[pl.second+1]) { d[pl.second+1] = dnow + c[pl.second+1]; st.insert(PL(d[pl.second+1], pl.second+1)); } if(pl.second < N*N && dnow + 1 < d[pl.second+1+N*N]) { d[pl.second+1+N*N] = dnow + 1; st.insert(PL(d[pl.second+1+N*N], pl.second+1+N*N)); } } } cout << d[2*N*N-1] << endl; }