#include using namespace std; #define rep(i,n) for(int i = 0; i < (n); ++i) #define rrep(i,n) for(int i = (n)-1; i >= 0; --i) #define chmax(a, b) a = max(a, b) #define chmin(a, b) a = min(a, b) #define all(x) (x).begin(), (x).end() #define rall(x) (x).rbegin(), (x).rend() using ll = long long; using P = pair; using VI = vector; using VVI = vector; using VL = vector; using VVL = vector; template std::vector dijkstra(std::vector>>& to, int s=0) { const unsigned long long INF = 1002003004005006007; struct QueElem { int v; unsigned long long c; bool operator<(const QueElem a) const {return c > a.c;} QueElem(int v, unsigned long long c): v(v), c(c) {} }; std::priority_queue q; std::vector dist(to.size(), INF); dist[s] = 0; q.emplace(s, 0); while(!q.empty()) { QueElem qe = q.top(); q.pop(); int u = qe.v; unsigned long long c = qe.c; if (c > dist[u]) continue; for(auto vc: to[u]) { int v = vc.first; unsigned long long nc = c + vc.second; if (nc < dist[v]) { dist[v] = nc; q.emplace(v, nc); } } } return dist; } int n; pair decode(int x) { pair ret; VI& s = ret.first; int& u = ret.second; s.resize(n); int t = 1; rep(_, n) t *= 3; u = x / t; x %= t; rep(i, n) { s[i] = x % 3; x /= 3; } return ret; } int encode(VI s, int u) { int ret = 0; int t = 1; rep(i, n) { ret += t * s[i]; t *= 3; } ret += t * u; return ret; } VVI c; vector>> to; void dfs(VI& s, int i=0) { if (i == n) { rep(orig, n) { if (s[orig] == 0) continue; int oi = encode(s, orig); rep(dest, n) { if (orig == dest) continue; if (s[dest] == 2) continue; s[dest]++; int di = encode(s, dest); to[oi].emplace_back(di, c[orig][dest]); s[dest]--; } } return; } rep(k, 3) { s[i] = k; dfs(s, i + 1); } } int pow3(int x) { int t = 1; rep(_, x) t *= 3; return t; } int main() { ios::sync_with_stdio(false); cin.tie(0); cin >> n; c = VVI(n, VI(n)); rep(i, n) rep(j, n) cin >> c[i][j]; int t = 1; rep(i, n) t *= 3; to.resize(t * n); vector s(n); dfs(s); for(int i = 0; i < n; ++i) { int dest = pow3(i) + t * i; to[0].emplace_back(dest, 0); } auto res = dijkstra(to); int a = t - 1; unsigned long long ans = 1002003004005006007; rep(u, n) { chmin(ans, res[t * u + a]); chmin(ans, res[t * u + a - pow3(u)]); } cout << ans << endl; }