#include<bits/stdc++.h>

using namespace std;

int main(){
  int n;
  int p,q;
  scanf("%d",&n);
  if(n==2){
    printf("? 2 1\n");
    fflush(stdout);
    scanf("%d%d",&p,&q);
    if(p==-1 && q==0){printf("! 3 2\n");}
    else{printf("! 2 3\n");}
    fflush(stdout);
    return 0;
  }
  map<pair<int,int>,vector<int>> mp;
  vector<pair<int,int>> ks1,ks2;
  int dmi=0,dma=0;
  vector<int> pmem(n*n-n+1),qmem(n*n-n+1);
  for(int i=2;i<=(n*n-n);i++){
    printf("? 1 %d\n",i);
    fflush(stdout);
    scanf("%d%d",&p,&q);
    pmem[i]=p;
    qmem[i]=q;
    ks1.push_back(make_pair(p,q));
    mp[make_pair(p,q)].push_back(i);
    if(p==q){
      dmi=min(dmi,p);
      dma=max(dma,p);
    }
  }
  int ky=(dma-dmi+1);
  int kh1=n+(n-ky),kh2=(n-ky)*n;
  //printf("<<%d %d>>\n",kh1,kh2);
  int dlt=(n+1)*(dma);
  kh1+=dlt;kh2+=dlt;
  for(int i=n;i<n*n;i++){
    if(i==kh1){continue;}
    p=(kh1/n)-(i/n);
    q=(kh1%n)-(i%n);
    if(p>q){swap(p,q);}
    ks2.push_back(make_pair(p,q));
  }
  sort(ks1.begin(),ks1.end());
  sort(ks2.begin(),ks2.end());
  int onev;
  if(ks1==ks2){onev=kh1;}
  else{onev=kh2;}
  vector<int> res(n*n-n+1,-1);
  res[1]=onev;
  int rp=(onev/n),rq=(onev%n);
  int base=-1,bv=-1;
  for(int i=2;i<=(n*n-n);i++){
    if(mp[make_pair(pmem[i],qmem[i])].size()>1){continue;}
    int cp,cq;
    cp=rp-pmem[i];
    cq=rq-qmem[i];
    if(1<=cp && cp<n && 0<=cq && cq<n){res[i]=cp*n+cq;continue;}
    cp=rp-qmem[i];
    cq=rq-pmem[i];
    res[i]=cp*n+cq;
    base=i;
    bv=res[i];
  }
  int bp=(bv/n),bq=(bv%n);
  for(int i=2;i<=(n*n-n);i++){
    if(mp[make_pair(pmem[i],qmem[i])].size()>1){
      int pr1=mp[make_pair(pmem[i],qmem[i])][0];
      int pr2=mp[make_pair(pmem[i],qmem[i])][1];
      int cp,cq;
      cp=rp-pmem[i];
      cq=rq-qmem[i];
      int pdp,pdq;
      pdp=bp-cp;
      pdq=bq-cq;
      if(pdp>pdq){swap(pdp,pdq);}
      printf("? %d %d\n",base,pr1);
      fflush(stdout);
      int acp,acq;
      scanf("%d%d",&acp,acq);
      if(pdp==acp && pdq==acq){
        res[pr1]=cp*n+cq;
        cp=rp-qmem[i];
        cq=rq-pmem[i];
        res[pr2]=cp*n+cq;
      }
      else{
        res[pr2]=cp*n+cq;
        cp=rp-qmem[i];
        cq=rq-pmem[i];
        res[pr1]=cp*n+cq;
      }
      mp[make_pair(pmem[i],qmem[i])].clear();
    }
  }
  printf("!");
  for(int i=1;i<=(n*n-n);i++){
    printf(" %d",res[i]);
  }printf("\n");
  fflush(stdout);
  return 0;
}