def f(N):
    if N == 1: return 1
    return N + f(N // 2)


def possible(flag):
    if flag: print('YES');exit()


N = int(input())
possible(N == 0)
# bisect
l, r = 0, 10 ** 9
while r - l > 1:
    m = (r + l) // 2
    possible(f(m) == N)

    if f(m) > N:
        r = m
    else:
        l = m
print('NO')