#include #include #include #include using namespace std; typedef long long ll; typedef pair pii; int di[4] = {-1, 0, 1, 0}; int dj[4] = {0, -1, 0, 1}; #define inRange(x,a,b) (a <= x && x < b) int main(){ int n, m; cin >> n >> m; int fee[n][n]; memset(fee, 0, sizeof(fee)); ll dp[2][n][n]; memset(dp, 0x3f, sizeof(dp)); dp[0][0][0] = 0; while(m--){ int x, y, z; cin >> x >> y >> z; fee[--x][--y] = z; } priority_queue> pq; pq.push({-0, {0, 0}}); while(!pq.empty()){ auto p = pq.top(); pq.pop(); ll c = -p.first; int x = p.second.first, i = p.second.second/n, j = p.second.second%n; if(dp[x][i][j] != c) continue; for(int k = 0; k < 4; k++){ int ni = i+di[k], nj = j+dj[k]; if(!inRange(ni,0,n)||!inRange(nj,0,n)) continue; ll nc = c+1+fee[ni][nj]; if(dp[x][ni][nj] > nc){ dp[x][ni][nj] = nc; pq.push({-nc, {x, ni*n+nj}}); } if(x) continue; nc -= fee[ni][nj]; if(dp[1][ni][nj] > nc){ dp[1][ni][nj] = nc; pq.push({-nc, {1, ni*n+nj}}); } } } cout << dp[1][n-1][n-1] << endl; return 0; }