// No.1307 Rotate and Accumulate
#include <bits/stdc++.h>

using namespace std;

void ntt(vector<long long> &a, bool inverse = false, long long mod = 998244353, int root = 3)
{
	auto pow = [&](long long x, long long n) {
		long long r = 1;
		for ( ; n > 0; x = x * x % mod, n >>= 1) if (n & 1) r = r * x % mod;
		return r;
	};
	int n = 1 << (32 - __builtin_clz(a.size() - 1));
	for (auto &x : a) x %= mod;
	if (a.size() < n) a.resize(n);
	vector<long long> r(32);
	for (int i = 0; i < r.size(); i++) r[i] = mod - pow(root, (mod - 1) >> (i + 2));

	if (!inverse) {
		for (int k = n >> 1; k; k >>= 1) {
			long long w = 1;
			for (int s = 0; s < n; s += k * 2, w = w * r[__builtin_ctz(s / k / 2)] % mod)
				for (int i = s, j = s + k; i < s + k; i++, j++) {
					long long u = a[i], v = a[j] * w % mod;
					// a[i] = (u + v) % mod;
					// a[j] = (u - v + mod) % mod;
					a[i] = u + v < mod ? u + v : u + v - mod;
					a[j] = u - v >= 0 ? u - v : u - v + mod;
				}
		}
	} else {
		vector<long long> ir(r.size());
		for (int i = 0; i < r.size(); i++) ir[i] = pow(r[i], mod - 2);
		for (int k = 1; k < n; k <<= 1) {
			long long w = 1;
			for (int s = 0; s < n; s += k * 2, w = w * ir[__builtin_ctz(s / k / 2)] % mod)
				for (int i = s, j = s + k; i < s + k; i++, j++) {
					long long u = a[i], v = a[j];
					// a[i] = (u + v) % mod;
					// a[j] = (u - v + mod) % mod * w % mod;
					a[i] = u + v < mod ? u + v : u + v - mod;
					a[j] = (u - v >= 0 ? u - v : u - v + mod) * w % mod;
				}
		}
		long long n_1 = pow(n, mod - 2);
		for (auto &x : a) x = x * n_1 % mod;
	}
}

vector<long long> multiply(const vector<long long> &a, const vector<long long> &b)
{
	vector<long long> fa(a.begin(), a.end()), fb(b.begin(), b.end());
	int n = 1 << (32 - __builtin_clz(a.size() + b.size() - 1));
	fa.resize(n); fb.resize(n);
	ntt(fa, false); ntt(fb, false);
	for (int i = 0; i < n; i++) fa[i] *= fb[i];
	ntt(fa, true);
	return fa;
}

int main(int argc, char *argv[])
{
	cin.tie(0)->sync_with_stdio(0);
	int n, q;
	cin >> n >> q;
	vector<int> a(n), r(q);
	for (auto &x : a) cin >> x;
	for (auto &x : r) cin >> x;

	vector<long long> f(n * 2), g(n + 1);
	for (int i = 0; i < n; i++) f[i] = f[i + n] = a[i];
	for (auto x : r) g[n - x]++;

	auto c = multiply(f, g);
	for (int i = n; i < n + n; i++) cout << (i > n ? " " : "") << c[i];
	cout << endl;

	return 0;
}