#include using namespace std; #define rep(i,n) for(ll i=0;i=0;i--) #define perl(i,r,l) for(ll i=(r)-1;i>=l;i--) #define fi first #define se second #define pb push_back #define ins insert #define pqueue(x) priority_queue,greater> #define all(x) (x).begin(),(x).end() #define CST(x) cout<; using vvl=vector>; using pl=pair; using vpl=vector; using vvpl=vector; const ll MOD=1000000007; const ll MOD9=998244353; const int inf=1e9+10; const ll INF=4e18; const ll dy[9]={1,0,-1,0,1,1,-1,-1,0}; const ll dx[9]={0,-1,0,1,1,-1,1,-1,0}; template inline bool chmin(T& a, T b) { if (a > b) { a = b; return true; } return false; } template inline bool chmax(T& a, T b) { if (a < b) { a = b; return true; } return false; } string s; ll n; ll solve(ll k,ll &now){ ll ans=0; rep(i,k){ if(now==0)ans++; else now--; now+=s[i%n]-'0'; } return ans; } struct seen{ ll pls,sum; }; int main(){ ll k;cin >> n >>k; string s;cin >> s; if(n<=10000000){ ll hoge=0; cout << solve(k,hoge) < v(n+1,{-1,-1}); ll now=0,ans=0,repeat=0; v[0]={0,0}; ll loopsum=-1; repl(t,1,10000){ ans+=solve(n,now); if(v[now].pls!=-1){ loopsum=ans-v[now].sum; ll rpt=k/n; rpt-=t; rpt/=t-v[now].pls; ans+=rpt*loopsum; repeat=t+rpt*(t-v[now].pls); repeat*=n; break; } v[now]={t,ans}; } ans+=solve(k-repeat,now); cout << ans <