#include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include using namespace std; using ll = long long; using P = pair; constexpr int INF = 1001001001; constexpr int mod = 1000000007; // constexpr int mod = 998244353; template inline bool chmax(T& x, T y){ if(x < y){ x = y; return true; } return false; } template inline bool chmin(T& x, T y){ if(x > y){ x = y; return true; } return false; } struct mint { int x; mint() : x(0) {} mint(int64_t y) : x(y >= 0 ? y % mod : (mod - (-y) % mod) % mod) {} mint& operator+=(const mint& p){ if((x += p.x) >= mod) x -= mod; return *this; } mint& operator-=(const mint& p){ if((x -= p.x) < 0) x += mod; return *this; } mint& operator*=(const mint& p){ x = (int)(1LL * x * p.x % mod); return *this; } mint& operator/=(const mint& p){ *this *= p.inverse(); return *this; } mint operator-() const { return mint(-x); } mint operator+(const mint& p) const { return mint(*this) += p; } mint operator-(const mint& p) const { return mint(*this) -= p; } mint operator*(const mint& p) const { return mint(*this) *= p; } mint operator/(const mint& p) const { return mint(*this) /= p; } bool operator==(const mint& p) const { return x == p.x; } bool operator!=(const mint& p) const { return x != p.x; } mint pow(int64_t n) const { mint res = 1, mul = x; while(n > 0){ if(n & 1) res *= mul; mul *= mul; n >>= 1; } return res; } mint inverse() const { return pow(mod - 2); } friend ostream& operator<<(ostream& os, const mint& p){ return os << p.x; } friend istream& operator>>(istream& is, mint& p){ int64_t val; is >> val; p = mint(val); return is; } }; mint dp[305][90005]; int main(){ ios::sync_with_stdio(false); cin.tie(nullptr); int N; cin >> N; vector A(N), B(N); for(int i = 0; i < N; ++i) cin >> A[i]; for(int i = 0; i < N; ++i) cin >> B[i]; ll gap = accumulate(A.begin(), A.end(), 0LL) - accumulate(B.begin(), B.end(), 0LL); if(gap < 0){ cout << -1 << endl; return 0; } if(N == 2){ if(gap != 0){ cout << -1 << endl; } cout << max(0, B[0] - A[0]) + max(0, B[1] - A[1]) << endl; return 0; } else if(gap % (N - 2) != 0){ cout << -1 << endl; return 0; } int ans = gap / (N - 2); ll sum = 0; for(int i = 0; i < N; ++i){ int need = B[i] - (A[i] - ans); if(need < 0 || need % 2 == 1){ cout << -1 << endl; return 0; } sum += need; } if(sum != 2 * ans) ans = -1; cout << ans << endl; return 0; }