#include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include using namespace std; #define REP(i,a,b) for(int i=a;i<(int)b;i++) #define REPLL(i,a,b) for(ll i=a;i<(ll)b;i++) #define rep(i,n) REP(i,0,n) #define all(c) (c).begin(), (c).end() #define zero(a) memset(a, 0, sizeof a) #define minus(a) memset(a, -1, sizeof a) #define minimize(a, x) a = std::min(a, x) #define maximize(a, x) a = std::max(a, x) using ll = long long; int const inf = 1<<29; #define double long double int main() { ll N, L, R; cin >> N >> L >> R; L = max(N, L); R = min(6 * N, R); if(N <= 3000) { if(L > inf) { cout << "0.000000000000000000000\n"; } double dp[22222]; // reuse array dp[0] = 1.0; rep(i, N) { for(int x=20000; x>=0; x--) { if(!dp[x]) { continue; } REP(k, 1, 7) { dp[x + k] += dp[x] / 6.0; } dp[x] = 0.0; } } double ret = 0.0; REPLL(i, max(0LL, L), min(R+1, 20000LL)) { ret += dp[i]; } printf("%.15f\n", ret); } else { double m = N * 3.5; double s = sqrt(N * 17.5/6.0); double supremum = erf((R + 0.5 - m) / (sqrt(2) * s)); double infimum = erf((L - 0.5 - m) / (sqrt(2) * s)); printf("%.15f\n", (supremum - infimum) / 2.0); } return 0; }