#include <iostream>
#include <math.h>
using namespace std;

int main(void)
{
    int n;
    int b;
    cin >> n;
    cin >> b;
    double sum1 = 0.0;
    double sum2 = 0.0;
    for(int i = 0; i < n; i++)
    {
        double a;
        cin >> a;
        sum1 += a * pow(b, a - 1);
        if(a != -1)
            sum2 += 1.0 / (a + 1.0) * pow(b, a + 1);
        else
            sum2 += log(b);
    }
    cout << sum1 << endl;
    cout << sum2 << endl;
    return 0;
}