# 遅延セグ木解 class LazySegmentTree: def __init__(self, op_X, e_X, mapping, compose, id_M, N, array=None): __slots__ = ["op_X","e_X","mapping","compose","id_M","N","log","N0","data","lazy"] self.e_X = e_X; self.op_X = op_X; self.mapping = mapping; self.compose = compose; self.id_M = id_M self.N = N self.log = (N-1).bit_length() self.N0 = 1<>i) self.data[p] = x for i in range(1, self.log + 1): self.update(p>>i) # 1点取得 def point_get(self, p): p += self.N0 for i in range(self.log, 0, -1): self.push(p>>i) return self.data[p] # 半開区間[L,R)をopでまとめる def prod(self, l, r): if l == r: return self.e_X l += self.N0 r += self.N0 for i in range(self.log, 0, -1): if (l>>i)<>i) if (r>>i)<>i) sml = smr = self.e_X while l < r: if l & 1: sml = self.op_X(sml, self.data[l]) l += 1 if r & 1: r -= 1 smr = self.op_X(self.data[r], smr) l >>= 1 r >>= 1 return self.op_X(sml, smr) # 全体をopでまとめる def all_prod(self): return self.data[1] # 1点作用 def apply(self, p, f): p += self.N0 for i in range(self.log, 0, -1): self.push(p>>i) self.data[p] = self.mapping(f, self.data[p]) for i in range(1, self.log + 1): self.update(p>>i) # 区間作用 def apply(self, l, r, f): if l == r: return l += self.N0 r += self.N0 for i in range(self.log, 0, -1): if (l>>i)<>i) if (r>>i)<>i) l2, r2 = l, r while l < r: if l & 1: self.all_apply(l, f) l += 1 if r & 1: r -= 1 self.all_apply(r, f) l >>= 1 r >>= 1 l, r = l2, r2 for i in range(1, self.log + 1): if (l>>i)<>i) if (r>>i)<>i) """ 始点 l を固定 f(x_l*...*x_{r-1}) が True になる最大の r つまり TTTTFFFF となるとき、F となる最小の添え字 存在しない場合 n が返る f(e_M) = True でないと壊れる """ def max_right(self, l, g): if l == self.N: return self.N l += self.N0 for i in range(self.log, 0, -1): self.push(l>>i) sm = self.e_X while True: while l&1 == 0: l >>= 1 if not g(self.op_X(sm, self.data[l])): while l < self.N0: self.push(l) l *= 2 if g(self.op_X(sm, self.data[l])): sm = self.op_X(sm, self.data[l]) l += 1 return l - self.N0 sm = self.op_X(sm, self.data[l]) l += 1 if l&-l == l: break return self.N """ 終点 r を固定 f(x_l*...*x_{r-1}) が True になる最小の l つまり FFFFTTTT となるとき、T となる最小の添え字 存在しない場合 r が返る f(e_M) = True でないと壊れる """ def min_left(self, r, g): if r == 0: return 0 r += self.N0 for i in range(self.log, 0, -1): self.push((r-1)>>i) sm = self.e_X while True: r -= 1 while r>1 and r&1: r >>= 1 if not g(self.op_X(self.data[r], sm)): while r < self.N0: self.push(r) r = 2*r + 1 if g(self.op_X(self.data[r], sm)): sm = self.op_X(self.data[r], sm) r -= 1 return r + 1 - self.N0 sm = self.op_X(self.data[r], sm) if r&-r == r: break return 0 # 以下内部関数 def update(self, k): self.data[k] = self.op_X(self.data[2*k], self.data[2*k+1]) def all_apply(self, k, f): self.data[k] = self.mapping(f, self.data[k]) if k < self.N0: self.lazy[k] = self.compose(f, self.lazy[k]) def push(self, k): #propagate と同じ if self.lazy[k] is self.id_M: return self.data[2*k ] = self.mapping(self.lazy[k], self.data[2*k]) self.data[2*k+1] = self.mapping(self.lazy[k], self.data[2*k+1]) if 2*k < self.N0: self.lazy[2*k] = self.compose(self.lazy[k], self.lazy[2*k]) self.lazy[2*k+1] = self.compose(self.lazy[k], self.lazy[2*k+1]) self.lazy[k] = self.id_M from math import cos,sin,radians,pi,sqrt n,q = map(int,input().split()) def f(a,b): x = a[0]+b[0] y = a[1]+b[1] return [x,y] def mapping(a,b): rotate = [[cos(radians(a)),-sin(radians(a))],[sin(radians(a)),cos(radians(a))]] x = b[0]*rotate[0][0]+b[1]*rotate[0][1] y = b[0]*rotate[1][0]+b[1]*rotate[1][1] return [x,y] def compose(a,b): return (a+b)%360 seg = LazySegmentTree(f,[0,0],mapping,compose,0,n,[[1,0] for i in range(n)]) arg = [0]*n length = [1]*n for _ in range(q): query = list(map(int,input().split())) if query[0] == 0: i,x = query[1:] seg.apply(i-1,n,(x-arg[i-1])%360) arg[i-1] = x elif query[0] == 1: i,x = query[1:] p,q = seg.point_get(i-1) l = sqrt(p**2+q**2) seg.point_set(i-1,[p*(x/l),q*(x/l)]) else: i = query[1] print(*seg.prod(0,i))