#include using namespace std; typedef long long ll; typedef pair p_ll; template void debug(T itr1, T itr2) { auto now = itr1; while(now=0; i--) const ll MOD = 998244353; const ll LLINF = pow(2,61)-1; const int INF = pow(2,30)-1; vector fac; void c_fac(int x=pow(10,6)+10) { fac.resize(x,true); rep(i,x) fac[i] = i ? (fac[i-1]*i)%MOD : 1; } ll modpow(ll x, ll p) { ll result = 1, now = 1, pm = x; while (now<=p) { if (p&now) { result = result * pm % MOD; } now*=2; pm = pm*pm % MOD; } return result; } ll inv(ll a, ll m=MOD) { ll b = m, x = 1, y = 0; while (b!=0) { int d = a/b; a -= b*d; swap(a,b); x -= y*d; swap(x,y); } return (x+m)%m; } ll nck(ll n, ll k) { return fac[n]*inv(fac[k]*fac[n-k]%MOD)%MOD; } ll gcd(ll a, ll b) { if (a x1, x2, theta; FastNumberTheoreticTransform(ll N=20) { size = 1< &v1, vector &v2) { size_x12 = v1.size() + v2.size() - 1; vsize = 0; while ((1<>vsize; x1 = v1; x2 = v2; x1.resize(1< convolution(vector &x, bool rev, ll depth=0, ll pos=0) { if (depth==vsize) return {x[pos]}; vector ex = convolution(x,rev,depth+1,pos); vector ox = convolution(x,rev,depth+1,pos+(1< result(N); rep(i,N) result[i] = (ex[i%(N/2)] + theta[base*(1< mul(vector &v1, vector &v2) { set(v1, v2); vector cx1 = convolution(x1, false), cx2 = convolution(x2, false); vector cx12(size); rep(i,size) cx12[i] = cx1[i] * cx2[i] % MOD; vector x12 = convolution(cx12, true); x12.resize(size_x12); return x12; } }; // ---------------------------------------------------------------------- // ---------------------------------------------------------------------- int main() { string S; cin >> S; ll N = S.size(); vector cnt(26,0); rep(i,N) cnt[S[i]-'a']++; sort(all(cnt)); // debug(all(cnt)); c_fac(); vector invfac(N+1); rep(i,N+1) invfac[i] = inv(fac[i]); FastNumberTheoreticTransform FNTT(15); vector v = {1}; rep(i,26) { rep(j,v.size()) v[j] = v[j] * invfac[j] % MOD; vector m(cnt[i]+1); rep(j,cnt[i]+1) m[j] = invfac[j]; v = FNTT.mul(v,m); rep(j,v.size()) v[j] = v[j] * fac[j] % MOD; } ll result = 0; repr(i,1,v.size()) result = (result+v[i]) % MOD; cout << result << endl; return 0; }