#include <atcoder/segtree>
#include <bits/stdc++.h>
using namespace std;
using namespace atcoder;
#define INF_LL 100000000000000000LL
#define INF 2000000000
#define MOD 1000000007
#define ll long long
#define all(x) x.begin(), x.end()
#define REP(i, a, b) for(int i = a; i < b; i++)
#define rep(i, n) REP(i, 0, n)
// typedef float double;
// typedef priority_queue prique;
typedef pair<ll, ll> P;
typedef vector<int> vi;
typedef vector<vi> vvi;
typedef vector<P> vp;
typedef vector<ll> vl;
typedef vector<vi> matrix;
int dx[4] = {0, 1, 0, -1};
int dy[4] = {1, 0, -1, 0};
int sign[2] = {1, -1};
template <class T> bool chmax(T &a, T b) {
    if(a < b) {
        a = b;
        return 1;
    }
    return 0;
}
template <class T> bool chmin(T &a, T b) {
    if(a > b) {
        a = b;
        return 1;
    }
    return 0;
}

ll modpow(ll a, ll b, ll m) {
    if(b == 0)
        return 1;
    ll t = modpow(a, b / 2, m);
    if(b & 1) {
        return (t * t % m) * a % m;
    } else {
        return t * t % m;
    }
}

struct edge {
    int to;
    ll cost;
    edge(int t, ll c) { to = t, cost = c; }
};
typedef vector<vector<edge>> graph;

// using mint = modint998244353;

int minop(int x, int y) {return min(x, y);}
int maxop(int x, int y) {return max(x, y);}
int mine() {return INF;}
int maxe() {return -INF;}

int main() {
    int n, q;
    cin >> n;
    vector<pair<int, int>> a(n);
    rep(i, n) {cin >> a[i].first;a[i].second = i;}
    segtree<int, maxop, maxe> seg1(n);
    segtree<int, minop, mine> seg2(n);
    rep(i, n) seg2.set(i, a[i].first);
    sort(all(a));
    cin >> q;
    vector<tuple<int, int, int, int>> query(q);
    rep(i, q){
        int l, r, x;
        cin >> l >> r >> x;
        query[i] = {x, l, r, i};
    }
    sort(all(query));
    int idx = 0;
    rep(i, q){
        int x, l, r, g;
        tie(x, l, r, g) = query[i];
        while(idx < n && x > a[idx].first){
            seg1.set(a[idx].second, seg2.get(a[idx].second));
            seg2.set(a[idx].second, mine());
            idx++;
        }
        get<0>(query[i]) = min(seg2.prod(l - 1, r) - x, x - seg1.prod(l - 1, r));
    }
    sort(begin(query), end(query), [](const auto &x, const auto &y){return get<3>(x) < get<3>(y);});
    rep(i, q){
        cout << get<0>(query[i]) << endl;
    }
    return 0;
}