/*** author: yuji9511 ***/ #include // #include // using namespace atcoder; using namespace std; using ll = long long; using lpair = pair; using vll = vector; const ll MOD = 1e9+7; const ll INF = 1e18; #define rep(i,m,n) for(ll i=(m);i<(n);i++) #define rrep(i,m,n) for(ll i=(m);i>=(n);i--) ostream& operator<<(ostream& os, lpair& h){ os << "(" << h.first << ", " << h.second << ")"; return os;} #define printa(x,n) for(ll i=0;i void print(H&& h, T&&... t){cout<(t)...);} void solve(){ ll n,m,p; cin >> n >> m >> p; vll a(n); rep(i,0,n) cin >> a[i]; vll cnt_p(n, 0); vll b(n); rep(i,0,n){ ll v = a[i]; while(v % p == 0){ v /= p; cnt_p[i]++; } b[i] = v; } rep(i,0,n){ if(a[i] > m){ print(1); return; } } bool ok = false; rep(i,0,n){ if(b[i] != 1) ok = true; } if(not ok){ print(-1); return; } ll max_val = 0; rep(i,0,n){ max_val = max(max_val,a[i]); } ll ans = INF; rep(i,0,n){ if(b[i] == 1) continue; ll res = 0, cur = 1; while(true){ if(cur * max_val > m){ res++; break; }else{ cur *= b[i]; res += 1 + cnt_p[i]; } } ans = min(ans, res); } print(ans); } int main(){ cin.tie(0); ios::sync_with_stdio(false); solve(); }