#dp[j][k] = 町ｊに所持金ｋ円で行く最短時間
N = int(input())
C = int(input())
V = int(input())
lsS = list(map(int,input().split()))
lsT = list(map(int,input().split()))
lsY = list(map(int,input().split()))
lsM = list(map(int,input().split()))
lsedge = []
for i in range(V):
    lsedge.append((lsS[i],lsT[i],lsY[i],lsM[i]))
lsedge.sort()
dp = [[float('INF')]*(C+1) for i in range(N+1) ]
dp[1][C] = 0
for i in range(1,V+1):
    from1 = lsedge[i-1][0]
    to = lsedge[i-1][1]
    cost = lsedge[i-1][2]
    time = lsedge[i-1][3]
    for k in range(C+1):
        if k - cost >= 0:
            dp[to][k-cost] = min(dp[to][k-cost],dp[from1][k]+time)
if min(dp[N]) == float('INF'):
    print(-1)
else:
    print(min(dp[N]))