/*** author: yuji9511 ***/ #include // #include // using namespace atcoder; using namespace std; using ll = long long; using lpair = pair; using vll = vector; const ll MOD = 1e9+7; const ll INF = 1e18; #define rep(i,m,n) for(ll i=(m);i<(n);i++) #define rrep(i,m,n) for(ll i=(m);i>=(n);i--) ostream& operator<<(ostream& os, lpair& h){ os << "(" << h.first << ", " << h.second << ")"; return os;} #define printa(x,n) for(ll i=0;i void print(H&& h, T&&... t){cout<(t)...);} vector factor(ll M){ vector fac; if(M == 1){ fac.push_back(1); return fac; } for(ll i = 2; i*i <= M; i++){ while(M % i == 0){ fac.push_back(i); M /= i; } } if(M != 1) fac.push_back(M); sort(fac.begin(), fac.end()); return fac; } vector divisor(ll M){ vector div; for(ll i = 1; i * i <= M; i++){ if(M % i == 0){ div.push_back(i); if(i * i != M) div.push_back(M / i); } } sort(div.begin(), div.end()); return div; } ll power(ll x, ll n, ll m = MOD){ if(n == 0) return 1LL; ll res = power(x * x % m, n/2, m); if(n % 2 == 1) (res *= x) %= m; return res; } void solve(){ ll N; cin >> N; while(N % 2 == 0) N /= 2; while(N % 5 == 0) N /= 5; if(N == 1){ print(1); return; } auto dd = factor(N); map mp; for(auto &e: dd) mp[e]++; ll r2 = 1; for(auto &e: mp){ if(e.second > 1){ rep(i,0,e.second-1){ r2 *= e.first; } } } for(auto &e: mp){ r2 *= e.first - 1; } auto div = divisor(r2); for(auto &e: div){ if(power(10,e,N) == 1){ print(e); return; } } } int main(){ cin.tie(0); ios::sync_with_stdio(false); ll t; cin >> t; while(t--) solve(); }