#include <iostream>
#include <string>
#include <cstring>
#include <cstdlib>
#include <cmath>
#include <algorithm>
#include <vector>
#include <set>
#include <map>
#include <queue>
#include <stack>
#include <list>
#include <iterator>
#include <cassert>
#include <numeric>
#include <functional>
#include <ctime>
#pragma warning(disable:4996) 

//#define ATCODER
#ifdef ATCODER
#include <atcoder/all>
#endif

typedef long long ll;
typedef unsigned long long ull;
#define LINF  9223300000000000000
#define LINF2 1223300000000000000
#define LINF3 1000000000000
#define INF 2140000000
//const long long MOD = 1000000007;
//const long long MOD = 998244353;
ll MOD;

using namespace std;
#ifdef ATCODER
using namespace atcoder;
#endif

ll mpow(ll x, ll n) { //x^n(mod M)
    ll ans = 1;
    while (n != 0) {
        if (n & 1) ans = ans * x % MOD;
        x = x * x % MOD;
        n = n >> 1;
    }
    return ans;
}

void solve()
{
    int n, K;
    scanf("%d%d%lld", &n, &K, &MOD);
    vector<vector<int> > a(4, vector<int>(n));
    int i,j;
    for (i = 0; i < 4; i++) {
        for (j = 0; j < n; j++) {
            scanf("%d", &a[i][j]);
        }
        sort(a[i].begin(), a[i].end());
    }
    ll ans = 0;
    for (i = 0; i < n; i++) {
        ll mm = min(min(a[0][i], a[1][i]), min(a[2][i], a[3][i]));
        ll MM = max(max(a[0][i], a[1][i]), max(a[2][i], a[3][i]));
        ll ans0 = mpow((MM - mm)%MOD, K);
        ans = (ans + ans0) % MOD;
    }
    printf("%lld\n", ans);

    return;
}

int main()
{
#if 1
    solve();
#else
    int T, t;
    scanf("%d",&T);
    for (t = 0; t < T; t++) {
        //cout << "Case #" << t + 1 << ": ";
        solve();
    }
#endif
    return 0;
}