#include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include using namespace std; using ll = long long; constexpr int INF = 1001001001; constexpr int mod = 1000000007; // constexpr int mod = 998244353; template inline bool chmax(T& x, T y){ if(x < y){ x = y; return true; } return false; } template inline bool chmin(T& x, T y){ if(x > y){ x = y; return true; } return false; } struct mint { int x; mint() : x(0) {} mint(int64_t y) : x(y >= 0 ? y % mod : (mod - (-y) % mod) % mod) {} mint& operator+=(const mint& p){ if((x += p.x) >= mod) x -= mod; return *this; } mint& operator-=(const mint& p){ if((x -= p.x) < 0) x += mod; return *this; } mint& operator*=(const mint& p){ x = (int)(1LL * x * p.x % mod); return *this; } mint& operator/=(const mint& p){ *this *= p.inverse(); return *this; } mint operator-() const { return mint(-x); } mint operator+(const mint& p) const { return mint(*this) += p; } mint operator-(const mint& p) const { return mint(*this) -= p; } mint operator*(const mint& p) const { return mint(*this) *= p; } mint operator/(const mint& p) const { return mint(*this) /= p; } bool operator==(const mint& p) const { return x == p.x; } bool operator!=(const mint& p) const { return x != p.x; } mint pow(int64_t n) const { mint res = 1, mul = x; while(n > 0){ if(n & 1) res *= mul; mul *= mul; n >>= 1; } return res; } mint inverse() const { return pow(mod - 2); } friend ostream& operator<<(ostream& os, const mint& p){ return os << p.x; } friend istream& operator>>(istream& is, mint& p){ int64_t val; is >> val; p = mint(val); return is; } }; long long extgcd(long long a, long long b, long long& x, long long& y){ long long g = a; if(b != 0){ g = extgcd(b, a % b, y, x); y -= (a / b) * x; } else{ x = 1, y = 0; } return g; } void solve(){ vector N(3); ll Y; cin >> N[0] >> N[1] >> N[2] >> Y; sort(rbegin(N), rend(N)); ll g = gcd(N[1], N[2]); N[1] /= g, N[2] /= g; mint ans = 0; for(ll i = 0; i <= Y / N[0]; ++i){ ll X = Y - N[0] * i; if(X % g != 0) continue; X /= g; ll p, q; ll _ = extgcd(N[1], N[2], p, q); ll upper, lower; if(q >= 0) upper = X * q / N[1]; else upper = (X * q - (N[1] - 1)) / N[1]; if(p < 0) lower = (-X * p + N[2] - 1) / N[2]; else lower = -X * p / N[2]; ans += upper - lower + 1; } cout << ans << '\n'; } int main(){ ios::sync_with_stdio(false); cin.tie(nullptr); int T; cin >> T; while(T--) solve(); return 0; }