#define _USE_MATH_DEFINES
#include <bits/stdc++.h>
using namespace std;
#define FOR(i,m,n) for(int i=(m);i<(n);++i)
#define REP(i,n) FOR(i,0,n)
#define ALL(v) (v).begin(),(v).end()
using ll = long long;
constexpr int INF = 0x3f3f3f3f;
constexpr long long LINF = 0x3f3f3f3f3f3f3f3fLL;
constexpr double EPS = 1e-8;
constexpr int MOD = 1000000007;
// constexpr int MOD = 998244353;
constexpr int dy[] = {1, 0, -1, 0}, dx[] = {0, -1, 0, 1};
constexpr int dy8[] = {1, 1, 0, -1, -1, -1, 0, 1}, dx8[] = {0, -1, -1, -1, 0, 1, 1, 1};
template <typename T, typename U> inline bool chmax(T &a, U b) { return a < b ? (a = b, true) : false; }
template <typename T, typename U> inline bool chmin(T &a, U b) { return a > b ? (a = b, true) : false; }
struct IOSetup {
  IOSetup() {
    std::cin.tie(nullptr);
    std::ios_base::sync_with_stdio(false);
    std::cout << fixed << setprecision(20);
  }
} iosetup;

bool is_kadomatsu(ll a, ll b, ll c) {
  return a != b && b != c && c != a && !(a < b && b < c) && !(a > b && b > c);
}

int main() {
  constexpr int N = 3;
  int a[N], b[N];
  REP(i, N) cin >> a[i];
  REP(i, N) cin >> b[i];
  REP(i, N) REP(j, N) {
    swap(a[i], b[j]);
    if (is_kadomatsu(a[0], a[1], a[2]) && is_kadomatsu(b[0], b[1], b[2])) {
      cout << "Yes\n";
      return 0;
    }
    swap(a[i], b[j]);
  }
  cout << "No\n";
  return 0;
}