#include //#include #define For(i, a, b) for (int(i) = (int)(a); (i) < (int)(b); ++(i)) #define rFor(i, a, b) for (int(i) = (int)(a)-1; (i) >= (int)(b); --(i)) #define rep(i, n) For((i), 0, (n)) #define rrep(i, n) rFor((i), (n), 0) #define fi first #define se second using namespace std; typedef long long lint; typedef unsigned long long ulint; typedef pair pii; typedef pair pll; template bool chmax(T& a, const T& b) { if (a < b) { a = b; return true; } return false; } template bool chmin(T& a, const T& b) { if (a > b) { a = b; return true; } return false; } template T div_floor(T a, T b) { if (b < 0) a *= -1, b *= -1; return a >= 0 ? a / b : (a + 1) / b - 1; } template T div_ceil(T a, T b) { if (b < 0) a *= -1, b *= -1; return a > 0 ? (a - 1) / b + 1 : a / b; } constexpr lint mod = 1000000007; constexpr lint INF = mod * mod; constexpr int MAX = 100010; bool check(deque& a, int i) { if (a[i] == a[i + 1] || a[i + 1] == a[i + 2] || a[i] == a[i + 2]) return false; return *max_element(a.begin() + i, a.begin() + i + 3) == a[i] || *min_element(a.begin() + i, a.begin() + i + 3) == a[i]; } lint solve(int n, deque& a) { lint dp[n + 1]; memset(dp, 0, sizeof(dp)); rep(i, n) { chmax(dp[i + 1], dp[i]); if (i + 3 <= n && check(a, i)) { chmax(dp[i + 3], dp[i] + a[i]); } } return dp[n]; } void solve() { int n; scanf("%d", &n); deque a(n); rep(i, n) scanf("%lld", &a[i]); lint ans = 0; rep(_, 3) { chmax(ans, solve(n, a)); auto x = a.front(); a.pop_front(); a.push_back(x); } printf("%lld\n", ans); } int main() { int t; scanf("%d", &t); rep(tt, t) solve(); }