#include <iostream>
#include <iomanip>
#include <vector>
#include <algorithm>
#include <numeric>
#include <functional>
#include <cmath>
#include <queue>
#include <stack>
#include <set>
#include <map>
#include <sstream>
#include <string>

#define repd(i,a,b) for (int i=(a);i<(b);i++)
#define rep(i,n) repd(i,0,n)
#define var auto
#define mod 1000000007
#define inf 2147483647
#define nil -1
typedef long long ll;

using namespace std;

inline int input(){
    int a;
    cin >> a;
    return a;
}

template <typename T>
inline void output(T a, int p) {
    if(p){
        cout << fixed << setprecision(p)  << a << "\n";
    }
    else{
        cout << a << "\n";
    }
}

// end of template

int dx[4] = {1, 0, -1, 0};
int dy[4] = {0, 1, 0, -1};

int main() {
    cin.tie(0);
    // source code
    int H = input();
    int W = input();
    vector<vector<int>> A(H, vector<int>(W));
    
    rep(i, H){
        rep(j, W){
            cin >> A[i][j];
        }
    }
    
    int Q = input();
    int count = 0; // 盤面が変化した回数

    queue<pair<int, int>> q;
    
    for (int i = 0; i < Q && count <= H + W; i++) {
        int R, C, X;
        cin >> R >> C >> X;
        R--, C--;
        if (A[R][C] == X) continue;
        q.push(make_pair(R, C));
        while (!q.empty()) {
            var t = q.front();
            q.pop();
            A[t.first][t.second] = X;
            rep(j, 4){
                if (t.first + dy[j] >= 0 && t.first + dy[j] < H && t.second + dx[j] >= 0 && t.second + dx[j] < W && A[t.first + dy[j]][t.second + dx[j]] != X) {
                    q.push(make_pair(t.first + dy[j], t.second + dx[j]));
                }
            }
        }
        count++;
        
    }
    
    rep(i, H){
        rep(j, W){
            if (j) cout << " ";
            cout << A[i][j];
        }
        cout << endl;
    }
    
    
    return 0;
}