#include #define rep(i,n) for(int i = 0; i < (n); ++i) #define drep(i,n) for(int i = (n)-1; i >= 0; --i) #define srep(i,s,t) for (int i = s; i < t; ++i) using namespace std; typedef long long int ll; typedef pair P; #define yn {puts("Yes");}else{puts("No");} struct edge{ ll to, cost; }; const ll INF = 1001001001001001001; const int MAX_N = 500005; const int MAX_V = 500005; vector G[MAX_V]; ll d[MAX_V]; void dijkstra(int s){ // greater

を指定することでfirstが小さい順に取り出せるようにする priority_queue, greater

> que; fill(d, d+MAX_V, INF); d[s] = 0; que.push(P(0, s)); while(!que.empty()){ P p = que.top(); que.pop(); int v = p.second; ll val = p.first; if(val > d[v]) continue; for(int i=0; i d[v] + e.cost){ d[e.to] = d[v] + e.cost; que.push(P(d[e.to], e.to)); } } } } int main() { ios_base::sync_with_stdio(false); cin.tie(0); int n, m; cin >> n >> m; srep(i,1,n+1){ edge e; e.to = i*2+1; e.cost = 0; G[i*2].push_back(e); } rep(i,m){ ll from,to,cost; cin >> from >> to >> cost; edge e; e.to = to * 2; e.cost = cost; G[from*2].push_back(e); e.to = from * 2; G[to*2].push_back(e); e.to = to * 2 + 1; G[from*2+1].push_back(e); e.to = from * 2 + 1; G[to*2+1].push_back(e); e.cost = 0; G[to*2].push_back(e); e.to = to * 2 + 1; G[from*2].push_back(e); } dijkstra(1*2); srep(i,1,n+1){ cout << d[i*2] + d[i*2+1] << endl; } return 0; }