#include <bits/stdc++.h>
//#include <atcoder/all>

using namespace std;
//using namespace atcoder;

using ll = long long;
using vll = vector<ll>;
using vvll = vector<vll>;
using pll = pair<ll, ll>;
using vpll = vector<pll>;
using ld = long double;
using vld = vector<ld>;
using vb = vector<bool>;

#define rep(i, n) for (ll i = 0; i < (n); i++)
#ifdef LOCAL
#define dbg(x) cerr << __LINE__ << " : " << #x << " = " << (x) << endl
#else
#define dbg(x) true
#endif

template <class T> bool chmin(T& a, T b) {
    if(a > b) { a = b; return true; }
    else return false;
}

template <class T> bool chmax(T& a, T b) {
    if(a < b) { a = b; return true; }
    else return false;
}

template <class T> ostream& operator<<(ostream& s, const vector<T>& a) {
    for(auto i : a) s << i << ' ';
    return s;
}

constexpr int INF = 1 << 30;
constexpr ll INFL = 1LL << 60;
constexpr ld EPS = 1e-12;
ld PI = acos(-1.0);

struct Edge {
    ll to, cap, rev;
    Edge(ll to, ll cap, ll rev) : to(to), cap(cap), rev(rev) {};
};

struct Dinic {
    ll n;
    vector<vector<Edge>> g;
    vector<ll> level, iter;
    Dinic(ll n) : n(n), g(n), iter(n) {};

    void add_edge(ll from, ll to, ll cap) {
        g[from].emplace_back(to, cap, (ll)g[to].size());
        g[to].emplace_back(from, 0, (ll)g[from].size()-1);
    }

    // 容量が残っているパスにおける始点からの距離を計算
    void bfs(ll s) {
        level.assign(n, -1);
        queue<ll> que;
        level[s] = 0;
        que.push(s);
        while(!que.empty()) {
            ll v = que.front();
            que.pop();
            for(ll i = 0; i < (ll)g[v].size(); ++i) {
                Edge& e = g[v][i];
                if(e.cap > 0 && level[e.to] < 0) {
                    level[e.to] = level[v] + 1;
                    que.push(e.to);
                }
            }
        }
    }

    // levelが増えるパスにおけるflowを計算
    ll dfs(ll v, ll t, ll f) {
        if(v == t) return f;
        // iter[v]を増やすことで各Edgeの探査は1回のみとする
        for(ll& i = iter[v]; i < (ll)g[v].size(); ++i) {
            Edge& e = g[v][i];
            if(e.cap > 0 && level[v] < level[e.to]) {
                ll d = dfs(e.to, t, min(f, e.cap));
                if(d > 0) {
                    e.cap -= d;
                    g[e.to][e.rev].cap += d;
                    return d;
                }
            }
        }
        return 0;
    }

    ll max_flow(ll s, ll t) {
        ll flow = 0;
        while(true) {
            bfs(s);
            if(level[t] < 0) return flow;
            iter.assign(n, 0);
            ll f;
            while((f = dfs(s, t, INFL)) > 0) { flow += f; }
        }
    }
};

void solve() {
    ll n, m, d;
    cin >> n >> m >> d;
    vll u(m), v(m), p(m), q(m), w(m);
    rep(i, m) cin >> u[i] >> v[i] >> p[i] >> q[i] >> w[i];

    Dinic D(2*m+2);
    rep(i, m) {
        D.add_edge(i, i+m, w[i]);
        if(u[i] == 1) D.add_edge(2*m, i, w[i]);
        if(v[i] == n) D.add_edge(i+m, 2*m+1, w[i]);
    }
    rep(fr, m) rep(to, m) {
        if(v[fr] == u[to] && q[fr] + d <= p[to]) {
            D.add_edge(fr+m, to, max(w[fr], w[to]));
        }
    }
    cout << D.max_flow(2*m, 2*m+1) << endl;
    return;
}

int main() {
    std::cin.tie(nullptr);
    std::ios_base::sync_with_stdio(false);
    cout << fixed << setprecision(15);
    solve();
}