from itertools import product

A,B = map(int,input().split())
A = str(A-1)
B = str(B)
mod=10**9+7

def count(a):
    n = len(a)
    dp=[[[[[0] * 8 for i in range(2)] for j in range(3)] for k in range(2)] for l in range(n+1)]
    dp[0][0][0][0][0] = 1

    for i, less, mod3, has3, mod8 in product(range(n), (0,1), range(3), (0,1), range(8)):
        max_d = 9 if less else int(a[i])
        for d in range(max_d+1):
            less_ = less or d < max_d
            mod3_ = (mod3*10+d)%3
            has3_ = has3 or d==3
            mod8_ = (mod8*10+d)%8
            dp[i + 1][less_][mod3_][has3_][mod8_] =  (dp[i + 1][less_][mod3_][has3_][mod8_]+dp[i][less][mod3][has3][mod8])%mod

    cnt = 0 
    for less,mod8 in product((0,1),range(1,8)):
        cnt = (cnt+dp[n][less][0][1][mod8])%mod
        cnt = (cnt+dp[n][less][1][1][mod8])%mod
        cnt = (cnt+dp[n][less][2][1][mod8])%mod
        cnt = (cnt+dp[n][less][0][0][mod8])%mod

    return cnt

print((count(B)-count(A))%mod)