#pragma GCC target("avx2")
#pragma GCC optimize("Ofast")
#pragma GCC optimize("unroll-loops")
//https://ideone.com/8AsuI2
#include <iostream>
#include <vector>
#include <cstdio>
#include <algorithm>
#include <functional>
#include <ctime>

using namespace std;

namespace bitmatrix {
typedef unsigned long long ull;
struct mat {
  int n, m;
  vector<vector<ull>> x;
  mat(int m, int n) : m(m), n(n), x(1+m/8, vector<ull>(1+n/8)) { }
  bool get(int i, int j) const {
    return x[i/8][j/8] & (1ull << (8*(i%8)+(j%8)));
  }
  void set(int i, int j, int b) {
    if (b) x[i/8][j/8] |=  (1ull << (8*(i%8)+(j%8)));
    else   x[i/8][j/8] &= ~(1ull << (8*(i%8)+(j%8)));
  }
};
ostream &operator<<(ostream &os, const mat &A) {
  for (int i = 0; i < A.m; ++i) {
    for (int j = 0; j < A.n; ++j)
      os << A.get(i, j);
    os << endl;
  }
  return os;
}
mat eye(int n) {
  mat I(n, n);
  for (int i = 0; i < I.x.size(); ++i)
    I.x[i][i] = 0x8040201008040201;
  return I;
}
mat add(mat A, const mat &B) {
  for (int i = 0; i < A.x.size(); ++i)
    for (int j = 0; j < A.x[0].size(); ++j)
      A.x[i][j] |= B.x[i][j];
  return A;
}
ull mul(ull a, ull b) { // C[i][j] |= A[i][k] & B[k][j]
  const ull u = 0xff, v = 0x101010101010101;
  ull c = 0;
  for (;a && b; a >>= 1, b >>= 8)
    c |= (((a & v) * u) & ((b & u) * v));
  return c;
}
mat mul(mat A, mat B) {
  mat C(A.n, B.m);
  for (int i = 0; i < A.x.size(); ++i)
    for (int k = 0; k < B.x.size(); ++k)
      for (int j = 0; j < B.x[0].size(); ++j)
        C.x[i][j] |= mul(A.x[i][k], B.x[k][j]);
  return C;
}
mat pow(mat A, long long k) {
  mat X = eye(A.n);
  for (; k > 0; k >>= 1) {
    if (k & 1ll) X = mul(X, A);
    A = mul(A, A);
  }
  return X;
}

ull transpose(ull a) {
  ull t = (a ^ (a >> 7)) & 0xaa00aa00aa00aa;
  a = a ^ t ^ (t << 7);
  t = (a ^ (a >> 14)) & 0xcccc0000cccc;
  a = a ^ t ^ (t << 14);
  t = (a ^ (a >> 28)) & 0xf0f0f0f0;
  a = a ^ t ^ (t << 28);
  return a;
}
mat transpose(mat A) {
  mat B(A.m, A.n);
  for (int i = 0; i < A.x.size(); ++i)
    for (int j = 0; j < A.x[0].size(); ++j)
      B.x[j][i] = transpose(A.x[i][j]);
  return B;
}
}

using namespace bitmatrix;

int main() {
  int n;
  cin >> n;
  long long t;
  cin >> t;
  mat A(n, n);
  string s;
  for(int i=0;i<n;i++){
    cin >> s;
    for(int j=0;j<n;j++){
      if(s[j]=='0'){A.set(i,j,0);}
      else{A.set(i,j,1);}
    }
  }
  A=pow(A,t);
  for(int i=0;i<n;i++){
    for(int j=0;j<n;j++){
      if(A.get(i,j)==0){puts("No");return 0;}
    }
  }
  puts("Yes");
  return 0;
}