#include <bits/stdc++.h>
using namespace std;
typedef signed long long ll;

#define _P(...) (void)printf(__VA_ARGS__)
#define FOR(x,to) for(x=0;x<(to);x++)
#define FORR(x,arr) for(auto& x:arr)
#define FORR2(x,y,arr) for(auto& [x,y]:arr)
#define ALL(a) (a.begin()),(a.end())
#define ZERO(a) memset(a,0,sizeof(a))
#define MINUS(a) memset(a,0xff,sizeof(a))
template<class T> bool chmax(T &a, const T &b) { if(a<b){a=b;return 1;}return 0;}
template<class T> bool chmin(T &a, const T &b) { if(a>b){a=b;return 1;}return 0;}
//-------------------------------------------------------

string N;
ll cur=1;
ll p45[101010];
const ll mo=1000000007;

void solve() {
	int i,j,k,l,r,x,y; string s;
	
	cin>>N;
	p45[0]=1;
	FOR(i,101000) p45[i+1]=p45[i]*45%mo;
	
	ll ret=0;
	FOR(i,N.size()) {
		x=N[i]-'0';
		if(x==0) {
			cur=0;
			break;
		}
		(ret+=cur*x*(x-1)/2%mo*p45[N.size()-1-i])%=mo;
		(cur*=x)%=mo;
	}
	ret+=cur;
	
	FOR(i,N.size()-1) ret+=p45[i+1];
	cout<<ret%mo<<endl;
	
	
}


int main(int argc,char** argv){
	string s;int i;
	if(argc==1) ios::sync_with_stdio(false), cin.tie(0);
	FOR(i,argc-1) s+=argv[i+1],s+='\n'; FOR(i,s.size()) ungetc(s[s.size()-1-i],stdin);
	cout.tie(0); solve(); return 0;
}