"""

v,2v,3v…みたいな？

mod xv+1 で考えればよい
後、順番は最後に並べ直せばよい

総和がxv+1の倍数

"""

import sys
from sys import stdin

def solve(lis,v,x):
    mod = v*x+1

    for i in range(1,x):
        now = 0
        for j in lis:
            now += pow(j,i,mod)
        if now % mod != 0:
            return False

    now = 0
    for j in lis:
        now += pow(j,x,mod)
    if now % mod != x:
        return False
    return True

TT = int(stdin.readline())

for loop in range(TT):

    v,x = map(int,stdin.readline().split())
    mod = v*x+1

    for j in range(1,x*v+1):
        a = [pow(j,i,mod) for i in range(x)]
        if solve(a,v,x):
            a.sort()
            print (*a)
            break