#include using namespace std; using ll = long long; using ld = long double; using pcc = pair; using pii = pair; using pll = pair; using pdd = pair; using tuplis = array; template using prique = priority_queue,greater>; #define rep(i,n) for(ll i = 0; i < n; i++) #define rrep(i,n) for(ll i = n-1; i >= 0; i--) #define all(a) a.begin(),a.end() #define rall(a) a.rbegin(),a.rend() #define Sort(a) sort(all(a)) #define Rev(a) reverse(all(a)) #define Uniq(a) sort(all(a));a.erase(unique(all(a)),a.end()) const ll LINF = 1001001001001001001; const int INF = 1001001001; const int MOD = 1000000007; const int MODD = 998244353; const ld PI = 3.1415926535897932; const ll dx[] = {0, 1, 0, -1, 1, -1, 1, -1}; const ll dy[] = {1, 0, -1, 0, 1, 1, -1, -1}; inline ll popcnt(ll a){ return __builtin_popcountll(a); } inline ll intpow(ll a, ll b){ ll ans = 1; while(b){ if(b & 1) ans *= a; a *= a; b /= 2; } return ans; } inline ll modpow(ll a, ll b, ll p){ ll ans = 1; while(b){ if(b & 1) (ans *= a) %= p; (a *= a) %= p; b /= 2; } return ans; } ll gcd(ll a,ll b){ if(a%b == 0){return b; } else{ return gcd(b,a%b); } } ll lcm(ll a,ll b){ return a/gcd(a,b)*b; } template bool chmin(T& a, const T& b){ if(a > b){ a = b; return 1; } return 0; } template bool chmax(T& a, const T& b){ if(a < b){ a = b; return 1; } return 0; } template bool chmin(T& a, const U& b){ if(a > T(b)){ a = b; return 1; } return 0; } template bool chmax(T& a, const U& b){ if(a < T(b)){ a = b; return 1; } return 0; } ll N,cnt[100005],used[100005],cnt2[100005],used2[100005],cnt3[100005]; vectorki[100005]; ll dfs(int now) { ll sum = 0; used[now] = true; rep(i,ki[now].size()) { if(used[ki[now][i]]) { continue; } sum += dfs(ki[now][i]); } return cnt[now] = sum+1; } ll dfs2(int now) { ll sum = 0; used2[now] = true; rep(i,ki[now].size()) { if(used2[ki[now][i]]) { continue; } sum += dfs2(ki[now][i]); } return cnt2[now] = sum+cnt[now]; } ll ans = 0; void dfs3(int now) { ll sum = 0; rep(i,ki[now].size()) { if(cnt[ki[now][i]] > cnt[now]) { sum += cnt3[ki[now][i]]-cnt2[now]-cnt[now]; } else { sum += cnt2[ki[now][i]]; } } cnt3[now] = sum+N; ans += cnt3[now]; rep(i,ki[now].size()) { if(cnt[ki[now][i]] > cnt[now]) { continue; } else { dfs3(ki[now][i]); } } } int main() { cin >> N; rep(i,N-1) { int A,B; cin >> A >> B; A--;B--; ki[A].push_back(B); ki[B].push_back(A); } dfs(0); dfs2(0); dfs3(0); cout << ans << endl; }