#include using namespace std; #define rep(i,n) for(ll i=0;i=0;i--) #define perl(i,r,l) for(ll i=r-1;i>=l;i--) #define fi first #define se second #define pb push_back #define ins insert #define pqueue(x) priority_queue,greater> #define all(x) (x).begin(),(x).end() #define CST(x) cout<; using vvl=vector>; using pl=pair; using vpl=vector; using vvpl=vector; const ll MOD=1000000007; const ll MOD9=998244353; const int inf=1e9+10; const ll INF=4e18; const ll dy[8]={-1,0,1,0,1,1,-1,-1}; const ll dx[8]={0,-1,0,1,1,-1,1,-1}; template inline bool chmin(T& a, T b) { if (a > b) { a = b; return true; } return false; } template inline bool chmax(T& a, T b) { if (a < b) { a = b; return true; } return false; } const int mod = 1000000007; const int max_n = 200005; struct mint { ll x; // typedef long long ll; mint(ll x=0):x((x%mod+mod)%mod){} mint operator-() const { return mint(-x);} mint& operator+=(const mint a) { if ((x += a.x) >= mod) x -= mod; return *this; } mint& operator-=(const mint a) { if ((x += mod-a.x) >= mod) x -= mod; return *this; } mint& operator*=(const mint a) { (x *= a.x) %= mod; return *this;} mint operator+(const mint a) const { return mint(*this) += a;} mint operator-(const mint a) const { return mint(*this) -= a;} mint operator*(const mint a) const { return mint(*this) *= a;} mint pow(ll t) const { if (!t) return 1; mint a = pow(t>>1); a *= a; if (t&1) a *= *this; return a; } bool operator==(const mint &p) const { return x == p.x; } bool operator!=(const mint &p) const { return x != p.x; } // for prime mod mint inv() const { return pow(mod-2);} mint& operator/=(const mint a) { return *this *= a.inv();} mint operator/(const mint a) const { return mint(*this) /= a;} }; istream& operator>>(istream& is, mint& a) { return is >> a.x;} ostream& operator<<(ostream& os, const mint& a) { return os << a.x;} mint calc(string s){ vector>> dp(s.size()+1,vector>(9,vector(2))); dp[0][0][0]=1; rep(i,s.size()){ ll p=s[i]-'0'; rep(j,9){ if(p==0){ } else if(p==5){ dp[i+1][min(j/3+1,2LL)*3+j%3][0]+=dp[i][j][0]; } else if(p==4||p==8){ dp[i+1][j-(j%3)+min(j%3+2,2LL)][0]+=dp[i][j][0]; } else if(p==2||p==6){ dp[i+1][j-(j%3)+min(j%3+1,2LL)][0]+=dp[i][j][0]; } else{ dp[i+1][j][0]+=dp[i][j][0]; } } rep(j,9){ for(int p=1;p<=9;p++){ if(p==0){ } else if(p==5){ dp[i+1][min(j/3+1,2LL)*3+j%3][1]+=dp[i][j][1]; } else if(p==4||p==8){ dp[i+1][j-(j%3)+min(j%3+2,2LL)][1]+=dp[i][j][1]; } else if(p==2||p==6){ dp[i+1][j-(j%3)+min(j%3+1,2LL)][1]+=dp[i][j][1]; } else{ dp[i+1][j][1]+=dp[i][j][1]; } } } ll t=p; rep(j,9){ for(int p=1;p> s; rep(i,10002){ rep(j,9){ dp[i+1][min(j/3+1,2LL)*3+j%3]+=dp[i][j]; dp[i+1][j-(j%3)+min(j%3+2,2LL)]+=dp[i][j]*2; dp[i+1][j-(j%3)+min(j%3+1,2LL)]+=dp[i][j]*2; dp[i+1][j]+=dp[i][j]*4; } } mint ans=0; //string t; rep(i,s.size()-1){ //t+='9'; //ans+=calc(t); ans+=dp[i+1][8]; //cout << ans <