#define _USE_MATH_DEFINES #include using namespace std; #define FOR(i,m,n) for(int i=(m);i<(n);++i) #define REP(i,n) FOR(i,0,n) #define ALL(v) (v).begin(),(v).end() using ll = long long; constexpr int INF = 0x3f3f3f3f; constexpr long long LINF = 0x3f3f3f3f3f3f3f3fLL; constexpr double EPS = 1e-8; constexpr int MOD = 1000000007; // constexpr int MOD = 998244353; constexpr int dy[] = {1, 0, -1, 0}, dx[] = {0, -1, 0, 1}; constexpr int dy8[] = {1, 1, 0, -1, -1, -1, 0, 1}, dx8[] = {0, -1, -1, -1, 0, 1, 1, 1}; template inline bool chmax(T &a, U b) { return a < b ? (a = b, true) : false; } template inline bool chmin(T &a, U b) { return a > b ? (a = b, true) : false; } struct IOSetup { IOSetup() { std::cin.tie(nullptr); std::ios_base::sync_with_stdio(false); std::cout << fixed << setprecision(20); } } iosetup; template struct BIT { BIT(int n, const Abelian UNITY = 0) : n(n), UNITY(UNITY), dat(n, UNITY) {} void add(int idx, Abelian val) { while (idx < n) { dat[idx] += val; idx |= idx + 1; } } Abelian sum(int idx) const { Abelian res = UNITY; --idx; while (idx >= 0) { res += dat[idx]; idx = (idx & (idx + 1)) - 1; } return res; } Abelian sum(int left, int right) const { return left < right ? sum(right) - sum(left) : UNITY; } Abelian operator[](const int idx) const { return sum(idx, idx + 1); } int lower_bound(Abelian val) const { if (val <= UNITY) return 0; int res = 0, exponent = 1; while (exponent <= n) exponent <<= 1; for (int mask = exponent >> 1; mask > 0; mask >>= 1) { if (res + mask - 1 < n && dat[res + mask - 1] < val) { val -= dat[res + mask - 1]; res += mask; } } return res; } private: int n; const Abelian UNITY; std::vector dat; }; template long long inversion_number(const std::vector &a) { int n = a.size(); std::vector comp(a); std::sort(comp.begin(), comp.end()); comp.erase(std::unique(comp.begin(), comp.end()), comp.end()); BIT bit(comp.size()); long long res = 0; for (int i = 0; i < n; ++i) { int idx = std::lower_bound(comp.begin(), comp.end(), a[i]) - comp.begin(); res += i - bit.sum(idx + 1); bit.add(idx, 1); } return res; } // https://atcoder.jp/contests/abc190/tasks/abc190_f int main() { int n; cin >> n; vector a(n); REP(i, n) cin >> a[i]; vector b = a; sort(ALL(b)); b.erase(unique(ALL(b)), b.end()); int m = b.size(); vector cnt(m, 0); REP(i, n) { a[i] = lower_bound(ALL(b), a[i]) - b.begin(); ++cnt[a[i]]; } FOR(i, 1, m) cnt[i] += cnt[i - 1]; ll ans = inversion_number(a); REP(i, n) { cout << ans << '\n'; ans += -(a[i] > 0 ? cnt[a[i] - 1] : 0) + (n - cnt[a[i]]); } return 0; }