#include //#include //#include //#include #define rep(i, a) for (int i = (int)0; i < (int)a; ++i) #define rrep(i, a) for (int i = (int)a - 1; i >= 0; --i) #define REP(i, a, b) for (int i = (int)a; i < (int)b; ++i) #define RREP(i, a, b) for (int i = (int)a - 1; i >= b; --i) #define pb push_back #define eb emplace_back #define all(x) x.begin(), x.end() #define rall(x) x.rbegin(), x.rend() #define popcount __builtin_popcount #define first fi #define second se using ll = long long; constexpr ll mod = 1e9 + 7; constexpr ll INF = 1LL << 60; // #pragma GCC target("avx2") // #pragma GCC optimize("O3") // #pragma GCC optimize("unroll-loops") //using lll=boost::multiprecision::cpp_int; //using Double=boost::multiprecision::number>;//仮数部が1024桁 template inline bool chmin(T &a, T b) { if (a > b) { a = b; return true; } return false; } template inline bool chmax(T &a, T b) { if (a < b) { a = b; return true; } return false; } template T mypow(T x, T n, const T &p = -1) { //x^nをmodで割った余り if(p!=-1){ x%=p; } T ret = 1; while (n > 0) { if (n & 1) { if (p != -1) ret = (ret * x) % p; else ret *= x; } if (p != -1) x = (x * x) % p; else x *= x; n >>= 1; } return ret; } using namespace std; //using namespace atcoder; void solve() { int n,k; cin>>n>>k; vector>dp(n+1,vector(n*6+5)),dp2(n+1,vector(n*6+5)); dp[0][0]=1;dp2[0][0]=1; rep(i,n){ for(int j=0;j<=i*6;++j){ rep(x,6){ if(j+x+1<=n*6)dp[i+1][j+(x+1)]+=dp[i][j]; } } } rep(i,n-k){ for(int j=0;j<=n*6;++j){ rep(x,6){ if(j+x+1<=n*6)dp2[i+1][j+(x+1)]+=dp2[i][j]; } } } rep(i,k){ for(int j=0;j<=n*6;++j){ for(int x=3;x<6;++x){ if(j+x+1<=n*6)dp2[n-k+i+1][j+(x+1)]+=dp2[n-k+i][j]*2; } } } double ans=0; for(int i=1;i<=n*6;++i){ for(int j=i+1;j<=n*6;++j){ ans+=dp[n][i]*dp2[n][j]; } } ans/=pow(6,n*2); cout<