#include using namespace std; // #include // using namespace atcoder; using ll = long long; using ld = long double; using vi = vector; using vvi = vector>; using vvvi = vector>>; using vl = vector; using vvl = vector>; using vvvl = vector>>; using vs = vector; using vb = vector; #define FOR(i, m, n) for (int i = (m); i < (n); i++) #define FORR(i, m, n) for (int i = (m); i >= (n); i--) #define REP(i, n) FOR(i, 0, (n)) #define REPR(i, n) FORR(i, (n) - 1, 0) #define REP1(i, n) FOR(i, 1, (n) + 1) #define REPS(c, s) for (char c : s) #define ALL(c) (c).begin(), (c).end() #define SORT(c) sort(ALL(c)) #define REV(c) reverse(ALL(c)) #define sz(v) (int)v.size() #define endl '\n' template inline bool chmin(T& a, T b) {if (a > b) {a = b; return true;} return false;} template inline bool chmax(T& a, T b) {if (a < b) {a = b; return true;} return false;} template inline void prn(vector& v) {int n = sz(v); REP(i, n) cout << v[i] << ' ';} template inline void printv(vector& v) {int n = sz(v); REP(i, n) cout << v[i] << (i == n - 1 ? endl : ' ');} template inline void printvv(vector>& v) {for (auto u : v) printv(u);} template inline void printvm(vector& v) {int n = sz(v); REP(i, n) cout << v[i].val() << (i == n - 1 ? endl : ' ');} template inline void printvvm(vector>& v) {for (auto u : v) printvm(u);} template inline void printlnv(vector& v) {int n = sz(v); REP(i, n) cout << v[i] << endl;} const int MOD = 1000000007; const int INF = 1000000001; const ll LINF = 1000000001000000001LL; void solve(); int main() { ios::sync_with_stdio(false); cin.tie(nullptr); cout << fixed << setprecision(numeric_limits::max_digits10); solve(); return 0; } void solve() { int n; cin >> n; vvi g(n, vi()); int a, b; REP(i, n - 1) { cin >> a >> b; a--; b--; g[a].emplace_back(b); g[b].emplace_back(a); } if (n <= 4) { cout << "Yes" << endl; return; } int c = -1; REP(i, n) { if (sz(g[i]) > 2) { if (c != -1) { cout << "No" << endl; return; } else { c = i; } } } if (c == -1) { cout << "Yes" << endl; return; } int ans = -1; function dfs = [&](int c, int p, int d) { if (sz(g[c]) == 1) { if (ans != -1 and ans != d) return false; else { ans = d; return true; } } bool ret = true; for (auto e : g[c]) { if (e == p) continue; ret &= dfs(e, c, d + 1); } return ret; }; cout << (dfs(c, -1, 0) ? "Yes" : "No") << endl; // cout << 100000 << endl; // REP(i, 99999) cout << "1 " << i + 1 << endl; }