#include #include #include #include #include #include #include #include #include #include #include #include #include #include #include using namespace std; #define REP(i,n) for(int i=0;i<(int)(n);i++) #define RREP(i,n) for(int i=n-1;i>=0;i--) #define FOR(i,k,n) for(int i=(k);i<(int)(n);i++) #define all(i,n) (i),(i+n) int dx4[4]={1,0,-1,0}; int dy4[4]={0,-1,0,1}; int dx8[8]={1,0,-1,1,-1,1,0,-1}; int dy8[8]={1,1,1,0,0,-1,-1,-1}; typedef pair P; typedef pair SP; typedef long long ll; typedef pair PLL; const int INF = 1e9; const ll LLINF = 1e18; const int MAX_V = 1e6+1; // const ll mod = 1e9 + 7; // cout << fixed << setprecision(10) // -------------------------------------- int n; int main() { cin.tie(0); ios::sync_with_stdio(false); cin >> n; vector a(n); REP(i, n) cin >> a[i]; int m = 0, ind = 0; for(; ind < n; ind++) { if(a[ind] < m) break; m = a[ind]; } if(ind == n) { cout << 0 << endl; return 0; } m = 0; FOR(i, ind, n) { if(a[i] < m) { cout << 2 << endl; return 0; } m = a[i]; } int mi = a[0], ma = a[ind - 1]; bool f = false; FOR(i, ind, n) { int now = a[i]; int next = (i == n - 1 ? INF + 10 : a[i + 1]); if(now <= mi && ma <= next) f = true; } cout << (f ? 1 : 2) << endl; }