import sys

sys.setrecursionlimit(10**6)
int1 = lambda x: int(x)-1
p2D = lambda x: print(*x, sep="\n")
def II(): return int(sys.stdin.buffer.readline())
def LI(): return list(map(int, sys.stdin.buffer.readline().split()))
def LI1(): return list(map(int1, sys.stdin.buffer.readline().split()))
def LLI(rows_number): return [LI() for _ in range(rows_number)]
def LLI1(rows_number): return [LI1() for _ in range(rows_number)]
def BI(): return sys.stdin.buffer.readline().rstrip()
def SI(): return sys.stdin.buffer.readline().rstrip().decode()
# dij = [(0, 1), (-1, 0), (0, -1), (1, 0)]
dij = [(0, 1), (-1, 0), (0, -1), (1, 0), (1, 1), (1, -1), (-1, 1), (-1, -1)]
inf = 10**16
# md = 998244353
md = 10**9+7

from functools import lru_cache

n, l, r = LI()
aa = LI()
# for a in aa: print(bin(a)[2:].zfill(12))

bb = [-1]*65

def chk(k, l, r):
    if k < 0: return True
    m = -1
    pb = aa[l] >> k & 1
    for i, a in enumerate(aa[l+1:r], l+1):
        b = a >> k & 1
        if b != pb:
            if m == -1:
                m = i
            else:
                return False
        pb = b
    if m == -1:
        if chk(k-1, l, r) == False: return False
    else:
        if bb[k] == -1:
            bb[k] = 1-pb
        elif bb[k] != 1-pb:
            return False
        if chk(k-1, l, m) == False: return False
        if chk(k-1, m, r) == False: return False
    return True

if chk(65, 0, n) == False:
    print(0)
    exit()

# kケタ見終わって、その桁以降が以下でもよい(1)か、未満でなければいけない(0)か
@lru_cache(None)
def solve(k, f):
    if k == 65: return f
    res = 0
    if f:
        if lim[k]:
            if bb[k] != 1: res += solve(k+1, 1)
            if bb[k] != 0: res += solve(k+1, 1)
        else:
            if bb[k] != 1: res += solve(k+1, 1)
            if bb[k] != 0: res += solve(k+1, 0)
    else:
        if lim[k]:
            if bb[k] != 1: res += solve(k+1, 1)
            if bb[k] != 0: res += solve(k+1, 0)
        else:
            if bb[k] != 1: res += solve(k+1, 0)
            if bb[k] != 0: res += solve(k+1, 0)
    return res

lim = [r >> k & 1 for k in range(65)]
# print(lim)
R = solve(0, 1)

solve.cache_clear()
L=0
if l>0:
    lim = [(l-1) >> k & 1 for k in range(65)]
    L = solve(0, 1)
# print(R, L)
print(R-L)