#include using namespace std; #define rep(i,n) for(ll i=0;i=0;i--) #define perl(i,r,l) for(ll i=r-1;i>=l;i--) #define fi first #define se second #define pb push_back #define ins insert #define pqueue(x) priority_queue,greater> #define all(x) (x).begin(),(x).end() #define CST(x) cout<; using vvl=vector>; using pl=pair; using vpl=vector; using vvpl=vector; ll MOD=1000000007; ll MOD9=998244353; int inf=1e9+10; ll INF=1e18; ll dy[8]={1,0,-1,0,1,1,-1,-1}; ll dx[8]={0,1,0,-1,1,-1,1,-1}; template inline bool chmax(T &a, T b) { return ((a < b) ? (a = b, true) : (false)); } template inline bool chmin(T &a, T b) { return ((a > b) ? (a = b, true) : (false)); } vvl solve1(ll n){ vvl mat(n,vl(n)); ll now=1,r=0,c=n/2; while(now<=n*n){ mat[r][c]=now; now++; r=(r-1+n)%n,c=(c+1+n)%n; if(mat[r][c]){ r=(r+2+n)%n,c=(c-1+n)%n; } } return mat; } vvl solve2(ll n){ vvl mat(n,vl(n)); ll now=1; rep(i,n){ rep(j,n){ if(abs(i-j)%4==0||(i+j)%4==3)mat[i][j]=now; now++; } } now=1; per(i,n){ per(j,n){ if(!(abs(i-j)%4==0||(i+j)%4==3))mat[i][j]=now; now++; } } return mat; } vvl solve3(ll n){ vvl pl=solve1(n/2); rep(i,n/2)rep(j,n/2)pl[i][j]=(pl[i][j]-1)*4; vvl lux(n/2,vl(n/2)); rep(i,n/2)lux[n/2/2+1][i]=1;//u rep(j,n/2){ for(int i=n/2/2+2;i> n; vvl mat; if(n%2)mat=solve1(n); else if(n%4==0)mat=solve2(n); else mat=solve3(n); rep(i,n){ rep(j,n)cout << mat[i][j] <<" ";cout << endl; } }