#include <bits/stdc++.h>

using namespace std;

typedef long long ll;

const ll INF = 1e+12;

#define REP(i, n) for (ll i = 0; i < n; ++i)
#define ALL(v) v.begin(), v.end()

int main()
{
  ll N, C;
  cin >> N >> C;

  vector<ll> P(N);
  REP(n, N) { cin >> P[n]; }
  sort(ALL(P), greater<ll>());

  vector<ll> cs1, cs2;
  REP(c, C) {
    ll T, X;
    cin >> T >> X;

    switch (T) {
    case 1:
      cs1.push_back(X);
      break;
    case 2:
      cs2.push_back(X);
      break;
    }
  }
  sort(ALL(cs1), greater<ll>());
  sort(ALL(cs2), greater<ll>());

  ll c1 = cs1.size(), c2 = cs2.size();
  vector<vector<ll>> dp(N + 1, vector<ll>(c1 + 1, INF));
  dp[0][0] = 0;
  REP(i, N) {
    REP(j, c1 + 1) {
      if (j > i) { continue; }
      ll k = i - j;

      dp[i + 1][j] = min(dp[i + 1][j], dp[i][j] + P[i]);

      if (j < c1) {
        ll cost = max(static_cast<ll>(0), P[i] - cs1[j]);
        dp[i + 1][j + 1] = min(dp[i + 1][j + 1], dp[i][j] + cost);
      }

      if (k < c2) {
        ll cost = P[i] - ((P[i] / 100) * cs2[k]);
        dp[i + 1][j + 0] = min(dp[i + 1][j + 0], dp[i][j] + cost);
      }
    }
  }
  cout << *min_element(ALL(dp[N])) << endl;

  return 0;
}