#define _USE_MATH_DEFINES #include using namespace std; #define FOR(i,m,n) for(int i=(m);i<(n);++i) #define REP(i,n) FOR(i,0,n) #define ALL(v) (v).begin(),(v).end() using ll = long long; constexpr int INF = 0x3f3f3f3f; constexpr long long LINF = 0x3f3f3f3f3f3f3f3fLL; constexpr double EPS = 1e-8; constexpr int MOD = 1000000007; // constexpr int MOD = 998244353; constexpr int dy[] = {1, 0, -1, 0}, dx[] = {0, -1, 0, 1}; constexpr int dy8[] = {1, 1, 0, -1, -1, -1, 0, 1}, dx8[] = {0, -1, -1, -1, 0, 1, 1, 1}; template inline bool chmax(T &a, U b) { return a < b ? (a = b, true) : false; } template inline bool chmin(T &a, U b) { return a > b ? (a = b, true) : false; } struct IOSetup { IOSetup() { std::cin.tie(nullptr); std::ios_base::sync_with_stdio(false); std::cout << fixed << setprecision(20); } } iosetup; long long mod_inv(long long a, int m) { if ((a %= m) < 0) a += m; if (std::__gcd(a, static_cast(m)) != 1) return -1; long long b = m, x = 1, u = 0; while (b > 0) { long long q = a / b; std::swap(a -= q * b, b); std::swap(x -= q * u, u); } x %= m; return x < 0 ? x + m : x; } template std::pair chinese_remainder_theorem(std::vector b, std::vector m) { T x = 0, md = 1; int n = b.size(); for (int i = 0; i < n; ++i) { if ((b[i] %= m[i]) < 0) b[i] += m[i]; if (md < m[i]) { std::swap(x, b[i]); std::swap(md, m[i]); } if (md % m[i] == 0) { if (x % m[i] != b[i]) return {0, 0}; continue; } T g = std::__gcd(md, m[i]); if ((b[i] - x) % g != 0) return {0, 0}; T ui = m[i] / g; x += (b[i] - x) / g % ui * mod_inv(md / g, ui) % ui * md; md *= ui; if (x < 0) x += md; } return {x, md}; } int main() { constexpr int N = 3; std::vector x(N), y(N); for (int i = 0; i < N; ++i) std::cin >> x[i] >> y[i]; long long ans, mod; std::tie(ans, mod) = chinese_remainder_theorem(x, y); if (mod == 0) { std::cout << "-1\n"; } else { std::cout << (ans == 0 ? mod : ans) << '\n'; } return 0; }