#include "bits/stdc++.h"
#define int long long
using namespace std;
using ll = long long;
//using P = pair<ll, pair<ll, ll>>;
const ll INF = (1LL << 61);
ll mod = 1000000007;
struct mint {
	ll x; // typedef long long ll;
	mint(ll x = 0) :x((x%mod + mod) % mod) {}
	mint operator-() const { return mint(-x); }
	mint& operator+=(const mint a) {
		if ((x += a.x) >= mod) x -= mod;
		return *this;
	}
	mint& operator-=(const mint a) {
		if ((x += mod - a.x) >= mod) x -= mod;
		return *this;
	}
	mint& operator*=(const mint a) {
		(x *= a.x) %= mod;
		return *this;
	}
	mint operator+(const mint a) const {
		mint res(*this);
		return res += a;
	}
	mint operator-(const mint a) const {
		mint res(*this);
		return res -= a;
	}
	mint operator*(const mint a) const {
		mint res(*this);
		return res *= a;
	}
	mint pow(ll t) const {
		if (!t) return 1;
		mint a = pow(t >> 1);
		a *= a;
		if (t & 1) a *= *this;
		return a;
	}

	// for prime mod
	mint inv() const {
		return pow(mod - 2);
	}
	mint& operator/=(const mint a) {
		return (*this) *= a.inv();
	}
	mint operator/(const mint a) const {
		mint res(*this);
		return res /= a;
	}
};
istream& operator>>(istream& is, mint& a) { return is >> a.x; }
ostream& operator<<(ostream& os, const mint& a) { return os << a.x; }
vector<int>a = { 6,2,5,5,4,5,6,4,7,6 };
int f(int n, string &x) {
	if (x[0] == '-') {
		x.erase(x.begin());
		int ans = f(n - 1, x);
		x = '-' + x;
		return 1 + ans;
	}
	if (x.size() == 1) {
		return a[x[0] - '0'];
	}
	else {
		char t = x.back();
		string a2 = ""; a2 += t;
		x.pop_back();
		int ans = f(n - 1, x);
		ans += f(n - 1, a2);
		x += t;
		return ans;
		
	}
}	
int f2(int n, int x) {
	
	if (x < 0) {
		return 1 + f2(n - 1, -x);
	}
	else if (x <= 9) {
		return a[x];
	}
	else {
		return f2(n - 1, x / 10) + f2(n - 1, x % 10);
	}
}
signed main() {
	ios::sync_with_stdio(false);
	cin.tie(0);
	string P, N; cin >> P >> N;
	int s = P.size();
	
	if (N.size() > 4) {
		int now = f(s, P);
		for (int i = 1; i < 10000; i++) {
			now = f2(s, now);
		}cout << now << endl;
	}
	else {
		int now = f(s, P);
		for (int i = 1; i <= atoi(N.c_str()) - 1; i++) {
			now = f2(s, now);
		}cout << now << endl;
	}
	return 0;
}