int n,k;
int dp[200010];
{
  rd(n, k);
  k += 1;
  dp[1] = k;
  REP(i, n) {
    if (!dp[i]) continue;
    if (i*2 <= n) {
      dp[i*2] = max(dp[i*2], dp[i]-1);
    }
    dp[i+3] = max(dp[i+3], dp[i]-1);
  }
  if (dp[n]) wt("YES"); else wt("NO");
}