def check(i,n,k):
    # 1,2,4,....,2**i 合計 k 回以下で n が作れる？
    return n//(1<<i) + bin(n%(1<<i)).count("1") <= k

n,k = map(int,input().split())
for i in range(20):
    nn = n-2**i
    if i > k or nn%3 or nn < 0: continue
    if check(i,nn//3,k-i):
        print("YES")
        exit()
print("NO")