/* Code for problem C by cookiedoth Generated 09 Apr 2021 at 03.34 PM █▒▒▒▒▒▒▒▒▒ 10% ███▒▒▒▒▒▒▒ 30% █████▒▒▒▒▒ 50% ███████▒▒▒ 70% ██████████ 100% ¯\_(ツ)_/¯ ^_^ -_- */ #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #define ll long long #define ld long double #define null NULL #define all(a) a.begin(), a.end() #define rall(a) a.rbegin(), a.rend() #define debug(a) cerr << #a << " = " << a << endl #define forn(i, n) for (int i = 0; i < n; ++i) #define length(a) (int)a.size() using namespace std; template int chkmax(T &a, T b) { if (b > a) { a = b; return 1; } return 0; } template int chkmin(T &a, T b) { if (b < a) { a = b; return 1; } return 0; } template void output(iterator begin, iterator end, ostream& out = cerr) { while (begin != end) { out << (*begin) << " "; begin++; } out << endl; } template void output(T x, ostream& out = cerr) { output(x.begin(), x.end(), out); } void fast_io() { ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0); } const int K = 26; const int mx = 1e4 + 228; int n, q; string s; int pref[mx][K]; signed main() { fast_io(); cin >> n >> q; cin >> s; for (int i = 0; i < n; ++i) { copy(pref[i], pref[i] + K, pref[i + 1]); pref[i + 1][s[i] - 'a']++; } for (int i = 0; i < q; ++i) { int l, r, x; cin >> l >> r >> x; l--; r--; x--; for (int j = 0; j < K; ++j) { if (x < pref[r + 1][j] - pref[l][j]) { cout << (char)('a' + j) << '\n'; break; } else { x -= pref[r + 1][j] - pref[l][j]; } } } }