//g++ 1.cpp -std=c++14 -O2 -I .
#include <bits/stdc++.h>
using namespace std;

#include <atcoder/all>
using namespace atcoder;

using ll = long long;
using ld = long double;

using vi = vector<int>;
using vvi = vector<vi>;
using vll = vector<ll>;
using vvll = vector<vll>;
using vld = vector<ld>;
using vvld = vector<vld>;

#define fi first
#define se second
#define pb push_back
#define pq_big(T) priority_queue<T,vector<T>,less<T>>
#define pq_small(T) priority_queue<T,vector<T>,greater<T>>
#define all(a) a.begin(),a.end()
#define rep(i,start,end) for(ll i=start;i<(ll)(end);i++)
#define per(i,start,end) for(ll i=start;i>=(ll)(end);i--)

constexpr ll mod = 998244353;

int main(){
  ios::sync_with_stdio(false);
  cin.tie(nullptr);


  clock_t start = clock(); 

  ll n,m;
  cin>>n>>m;

  ll pow2=1,factional=1;

  //fac[i] := i! (i=0のときfac[i]=1)
  vll fac(n+100);
  vll invfac(n+100);
  rep(i,0,n+50){
    fac[i]=factional;
    invfac[i]=inv_mod(fac[i],mod);
    factional*=(i+1);
    factional%=mod;
  }

  //mul := FFTするときにかけるやつ　0 + (2^1 - 1)/(2^1 * 1!) x + (2^2 - 1)/(2^2 * 2!) x^2 + ... といった具合
  vll mul(n+1,0);
  rep(i,1,n+1){
    pow2*=2;
    pow2%=mod;
    mul[i]=pow2-1;
    mul[i]*=inv_mod(pow2*fac[i],mod);
    mul[i]%=mod;
    //cout<<mul[i]<<" ";
  }
  //cout<<endl;

  //now := 今のdp配列を多項式にして保存
  //count[i] := mex>=iとなるようなA'の数(を全通りの数列に対して足し合わせた合計)
  vll now(1,1);
  vll count(n+1,0);
  rep(i,0,min(n,m+1)){

    /*

    now=move(convolution(now,mul));
    while(now.size()>n+10){
      now.pop_back();
    }
    rep(j,0,n+1){
      //cout<<get[j]<<" ";
      now.pb(now[j]);

      //pow_modのところは残りを埋める方法を反映
      //inv_modのところは二項係数の整理 100C2 * 98C4 = 100!/(2! * 98!) * 98!/(4! * 94!) = 100!(2! * 4! * 94!) の94!のところ

      count[i]+=(now[j]*pow_mod(m-i,n-j,mod))%mod*invfac[n-j];
      count[i]%=mod;
    }

    */


    

    vll get=convolution(now,mul);
    now.clear();
    rep(j,0,n+1){
      //cout<<get[j]<<" ";
      now.pb(get[j]);

      //pow_modのところは残りを埋める方法を反映
      //inv_modのところは二項係数の整理 100C2 * 98C4 = 100!/(2! * 98!) * 98!/(4! * 94!) = 100!(2! * 4! * 94!) の94!のところ

      count[i]+=(get[j]*pow_mod(m-i,n-j,mod))%mod*invfac[n-j];
      count[i]%=mod;
    }

    

    //cout<<endl;
  }

  ll ans=0,p=(pow2*fac[n])%mod;

  rep(i,0,n+1){
    //一括して2^N * N! をかける

    count[i]*=p;
    count[i]%=mod;

    //cout<<count[i]<<" ";
  }

  per(i,n,0){
    //count[i]の差分を取ることで各mexごとに値が求まる

    ans+=count[i]*(i+1);
    ans%=mod;
    ans+=mod;
    if(i>0){
      count[i-1]-=count[i];
      count[i-1]%=mod;
    }
  }

  cout<<(ans%mod+mod)%mod<<endl;



  clock_t end = clock();     // 終了時間
  //cout << "duration = " << (double)(end - start) / CLOCKS_PER_SEC << "sec.\n";
}