#include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #define popcount __builtin_popcount using namespace std; using namespace atcoder; typedef long long ll; typedef pair P; int n; int p[200020]; ll a[200020]; ll ans[200020]; void solve(int l, int r){ if(l==r){ if(p[l]<=a[p[l]]) ans[p[l]]++; return; } int m=(l+r)/2; solve(l, m); solve(m+1, r); vector vl1(m-l+2), vr1(r-m+1); vector vl2(m-l+2), vr2(r-m+1); vl1[0]=1e9, vr1[0]=1e9; for(int i=m; i>=l; i--){ vl1[m-i+1]=min(vl1[m-i], p[i]); vl2[m-i+1]=vl2[m-i]+p[i]; } for(int i=m+1; i<=r; i++){ vr1[i-m]=min(vr1[i-m-1], p[i]); vr2[i-m]=vr2[i-m-1]+p[i]; } for(int i=1; i<=m-l+1; i++){ int mn=vl1[i]; ll s=vl2[i]; int k1=lower_bound(vr1.begin(), vr1.end(), mn, greater())-vr1.begin(); int k2=upper_bound(vr2.begin(), vr2.end(), a[mn]-s)-vr2.begin(); if(min(k1, k2)>0) ans[mn]+=min(k1, k2)-1; } for(int i=1; i<=r-m; i++){ int mn=vr1[i]; ll s=vr2[i]; int k1=lower_bound(vl1.begin(), vl1.end(), mn, greater())-vl1.begin(); int k2=upper_bound(vl2.begin(), vl2.end(), a[mn]-s)-vl2.begin(); if(min(k1, k2)>0) ans[mn]+=min(k1, k2)-1; } } int main() { cin>>n; for(int i=1; i<=n; i++){ cin>>p[i]; } for(int i=1; i<=n; i++){ cin>>a[i]; } solve(1, n); for(int i=1; i<=n; i++){ cout<