#include int main(void) { int n; int i; double a; int sum = 0; int x[100001]; scanf("%d", &n); for(i = 0;i < n;i++){ scanf("%d", &x[i]); sum += x[i]; } a = (double)sum / n; for(i = 0;i < n;i++){ printf("%d\n", (int)(50 - (a - x[i]) / 2)); } return 0; }