import collections
import heapq


class Dijkstra:
    def __init__(self):
        self.e = collections.defaultdict(list)

    def add(self, u, v, d):
        self.e[u].append([v, d])
        self.e[v].append([u, d])

    def delete(self, u, v):
        self.e[u] = [_ for _ in self.e[u] if _[0] != v]
        self.e[v] = [_ for _ in self.e[v] if _[0] != u]

    def search(self, s):
        """
        :param s: 始点
        :return: 始点から各点までの最短経路
        """
        d = collections.defaultdict(lambda: float('inf'))
        d[s] = 0
        q = []
        heapq.heappush(q, (0, s))
        v = collections.defaultdict(bool)
        while len(q):
            k, u = heapq.heappop(q)
            if v[u]:
                continue
            v[u] = True

            for uv, ud in self.e[u]:
                if v[uv]:
                    continue
                vd = k + ud
                if d[uv] > vd:
                    d[uv] = vd
                    heapq.heappush(q, (vd, uv))

        return d

N, M = map(int, input().split())
ABC = [list(map(int, input().split())) for i in range(M)]
graph1 = Dijkstra()#チケット使用しない
graph2 = Dijkstra()#チケット1枚使用(使用後をマイナスで表現)
for a,b,c in ABC:
    graph1.add(a, b, c)
    graph2.add(a, b, c)
    graph2.add(a, -b, 0)
    graph2.add(-a, -b, c)
g1 = graph1.search(1)
g2 = graph2.search(1)
print(0)#1から1は0、↓の計算でやると別な値が入るため
for i in range(2,N+1):
    print(g1[i]+g2[-i])