#include <iostream>
using namespace std;

int N;
int E[20];
int power3[20];

int main() {
	// Step #1. 入力
	cin >> N;
	for (int i = 0; i < N; i++) cin >> E[i];

	// Step #2. 前処理
	power3[0] = 1;
	for (int i = 1; i <= N; i++) power3[i] = 3 * power3[i - 1];

	// Step #3. 探索
	for (int i = 0; i < power3[N]; i++) {
		int sumA = 0, sumB = 0, sumC = 0;
		for (int j = 0; j < N; j++) {
			int bit = (i / power3[j]) % 3;
			if (bit == 0) sumA += E[j];
			if (bit == 1) sumB += E[j];
			if (bit == 2) sumC += E[j];
		}
		if (sumA == sumB && sumB == sumC) {
			cout << "Yes" << endl;
			return 0;
		}
	}
	cout << "No" << endl;
	return 0;
}