#include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include using namespace std; #define REP(i,a,b) for(int i=a;i<(int)b;i++) #define rep(i,n) REP(i,0,n) #define all(c) (c).begin(), (c).end() #define zero(a) memset(a, 0, sizeof a) #define minus(a) memset(a, -1, sizeof a) #define minimize(a, x) a = std::min(a, x) #define maximize(a, x) a = std::max(a, x) typedef long long ll; int const inf = 1<<29; ll solve(string const& S, bool last) { const int N = S.size(); ll ret = 0; ll dp[14][2][2][14*14]; // i桁目, 最大値未満, 前の桁が'1', "12"の個数 zero(dp); dp[0][0][0][0] = 1; rep(i, N) rep(less, 2) rep(prevone, 2) rep(twcount, 14*14) { auto const& curr = dp[i][less][prevone][twcount]; const int dmax = less ? 9 : (S[i] - '0'); rep(d, dmax + 1) { auto const ni = i + 1; auto const nprevone = d == 1; auto const nless = less || (d < dmax); auto const ntwcount = twcount + (prevone && d == 2); auto& next = dp[ni][nless][nprevone][ntwcount]; next += curr; } } rep(i, 2) rep(j, 2) rep(k, 14*14) { ret += dp[N][i][j][k] * k; } if(last) { rep(i, 2) rep(j, 14*14) { ret -= dp[N][0][i][j] * j; } } return ret; } ll count2_2(string const& S, bool last) { int N = S.size(); ll dp[14][2][2][2][2]; // i桁目, 最大値未満, 前の桁が'2', leading0, はじめの桁が'2' zero(dp); dp[0][0][0][1][0] = 1; rep(i, N) rep(less, 2) rep(prev2, 2) rep(leading0, 2) rep(start2, 2) { auto const& curr = dp[i][less][prev2][leading0][start2]; int dmax = less ? 9 : (S[i] - '0'); rep(d, dmax + 1) { auto const ni = i + 1; auto const nless = less || (d < dmax); auto const nprev2 = d == 2; auto const nleading0 = leading0 && (d == 0); auto const nstart2 = start2 || (leading0 && (d == 2)); auto& next = dp[ni][nless][nprev2][nleading0][nstart2]; next += curr; } } ll ret = 0; rep(i, 2) { if(last && i == 0) { continue; } ret += dp[N][i][1][0][1]; } return ret; } int main() { string A, B; cin >> A >> B; /* cout << solve(A, false) << endl; cout << solve(B, false) << endl; cout << "::" << count2_2(A, true) << endl; cout << count2_2(B, false) << endl; */ cout << solve(B, false) - solve(A, true) + count2_2(B, false) - (count2_2(A, true) + (A.back() != '2')) << endl; return 0; }