#include using namespace std; int main () { int n; cin >> n; vector a(n); for (int i = 0; i < n; i++) { cin >> a[i]; } long long sum = 1LL * (1 + n) * n / 2; int now = 0; for (int i = 0; i < n; i++) { if (a[i] == 1) { now++; } else { sum -= 1LL * (now + 1) * now / 2; now = 0; } } sum -= 1LL * (now + 1) * now / 2; cout << sum << endl; return 0; }